All categories

2 years ago

What is the distance between (5, -1) and (5,-4)

Mathematics

1 answer:

jarptica [38.1K]2 years ago

3 0

Answer:

Step-by-step explanation:

To evaluate for such, the following comprehension is required,

Equation Required: Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2

Denote the configurations as the following,

(5, -1). (5, -4)

X1 Y1. X2. Y2

D(P, Q) = √(5 - 5)^2 + (-4 +1)^2. <== Since the double negative is present, the operation is acknowledged as positive.

D(P, Q) = √(0)^2 + (-3)^2

D(P, Q) = √9 = 3

Thus, the agglomerate distance between the points situated in the Cartesian plane is disclosed, and is, henceforth, disseminated as 03 units.

You might be interested in

Joel made egg sandwiches and tuna sandwiches in the ratio 2:3. He then made 15 more tuna sandwiches and the ratio changed to 1:3

Ksenya-84 [330]

So 2e:3t 3t+15=1e:3e so

2e:3t
3t+15
1e:3t
1e:3t=2e:6t
so 2e:6e
2e:3t+15=2e:6t
15=3t
t=5
2+3=5 units
5 times 5=25
he made 25 samiches in all
check
e:t=10:15=2:3
15+15=30
10:30=1:3
checks

he made 25 sammiches origonaly

8 0

2 years ago

Melanie was training for a race. The line plot below shows the number of miles Melanie ran last week.

aliya0001 [1]

3/4+1/4=1
I’m not sure why you put the thing about Melanie there.

7 0

2 years ago

harry is trying tq solve the equation y=2x^2 -x-6 using the quadratic formula he has made an error in one of the steps below

Sergeeva-Olga [200]

Answer:

Hello :

y = 2x² - x -6

y = 2 ( x² - 1/2 x - 3)

y = 2 (x² -1/2 x + 1/16 -1/16 -3)

y = 2 (( x - 1/4 )² - 49/16)..... the quadratic formula

y = 0 : ( x - 1/4 )² - 49/16 = 0

( x - 1/4 )² - (7/4)² = 0

( x -1/4-7/4)( x -1/4+7/4)=0

(x -2)(x + 3/2) = 0

x - 2 = 0 or x + 3/2 =0

x = 2 or x = - 3/2

3 0

2 years ago

Find the equation of the line through point (2,−4) and parallel to −6x+2y=4. Use a forward slash (i.e. "/") for fractions (e.g.

chubhunter [2.5K]

Answer:

y = 3x - 10

Step-by-step explanation:

Step 1: Rewrite 1st equation

2y = 6x + 4

y = 3x + 4

Step 2: Find 2nd equation

y = 3x + b

-4 = 3(2) + b

-4 = 6 + b

b = -10

Step 3: Rewrite 2nd equation

y = 3x - 10

And we have your parallel equation!

5 0

2 years ago

A ship is sailing due north. At a certain point the bearing of a lighthouse is N 42.8∘E and the distance is 10.5. After a while,

bija089 [108]

Answer:

How far did the ship travel between the two observations of the lighthouse = 9.29

Step-by-step explanation:

the first step to answer this question is drawing the illustration as the attachment.

P is the ship, R is the light house and Q is the bearing.

PR is the distance between the ship and the light house, PR = 10.5

∠P = 42.8°, ∠Q = 59.7°

Thus, ∠R = 180° - ∠P - ∠Q

= 180° - 42.8°- 59.7°

= 77.5°

PQ is the the distance of the ship moving. We can use the sinus equation

$\frac{PR}{sin R}$ = $\frac{PQ}{sin Q}$

$\frac{10.5}{sin 77.5°}$ = $\frac{PQ}{sin 59.7°}$

PQ = ( $\frac{10.5}{Sin 77.5°}$ )(sin 59.7°)

= 9.29

5 0

2 years ago