Question

What is the distance between (5, -1) and (5,-4)

Answer 1

Answer:

Step-by-step explanation:

To evaluate for such, the following comprehension is required,

Equation Required: Distance Formula: d(P, Q) = √ (x2 − x1)^2 + (y2 − y1)^2

Denote the configurations as the following,

(5, -1). (5, -4)

X1 Y1. X2. Y2

D(P, Q) = √(5 - 5)^2 + (-4 +1)^2. <== Since the double negative is present, the operation is acknowledged as positive.

D(P, Q) = √(0)^2 + (-3)^2

D(P, Q) = √9 = 3

Thus, the agglomerate distance between the points situated in the Cartesian plane is disclosed, and is, henceforth, disseminated as 03 units.