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wolverine [178]
3 years ago
9

1.For Structure B the bond between carbon and sulfur is polar or non polar

Chemistry
1 answer:
Inga [223]3 years ago
3 0

Answer:

polar

Explanation:

because carbon and sulfur have different electronegativities, the S=C bond is polar.

The entire molecule is nonpolar however because the dipoles (polar bonds) cancel out due to the geometry of the molecule (linear)

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A 50.0 50.0 mL solution of 0.127 0.127 M KOH KOH is titrated with 0.254 0.254 M HCl HCl. Calculate the pH of the solution after
Brilliant_brown [7]

Answer:

Explanation:

THE CORECT QUESTION

A 50.0 mL solution of 0.127 M KOH is titrated with 0.254 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCl.

SOLUTION

Get the concentration of the HCl first using titration formula

CA X V A / CB VB = NA/ NB

Equation of reation; KOH + HCl => KCl + H2O

CA = 0.254 M

CB = 0.127

VA = 1/0.254 = 3.937

CA (after the addition) = 0.127 x 50 / 3.937

                                     = 1.612 M

But pH = - Log[hydrogen ion]

            = -log 1.612

            =

8 0
2 years ago
Please help Sodium (Na) has an atomic number of 11 and an atomic mass of 23. Which of the following correctly shows the electron
fredd [130]
2,8,1
It's in group 1, so its outershell only has 1 electron, and the other shells are completely filled, so 2 then 8. :)
3 0
3 years ago
How did Henry Moseley revise Mendeleev's periodic table? (Please answer A.S.A.P.)
CaHeK987 [17]
<span>If you give it a good search, the most used answer would probably be as follows,

</span><span>In 1914 Henry Moseley found a relationship between an element's X-ray wavelength and its atomic number (Z), and therefore rearranged the table by nuclear charge / atomic number rather than atomic weight. Before this discovery, atomic numbers were just sequential numbers based on an element's atomic weight. Moseley's discovery showed that atomic numbers had an experimentally measurable basis.
</span>
Hope this helps!
5 0
3 years ago
Read 2 more answers
g A laboratory analysis of an unknown compound found the following composition: C 75.68% ; H 8.80% ; O 15.52%. What is the empir
sammy [17]

Answer:

THE EMPIRICAL FORMULA FOR THE UNKNOWN COMPOUND IS C7H9O

Explanation:

The empirical formula for the unknown compound can be obtained by following the processes below:

1 . Write out the percentage composition of the individual elements in the compound

C = 75.68 %

H = 8.80 %

O = 15.52 %

2. Divide the percentage composition by the atomic masses of the elements

C = 75 .68 / 12 = 6.3066

H = 8.80 / 1 = 8.8000

O = 15.52 / 16 = 0.9700

3. Divide the individual results by the lowest values

C = 6.3066 / 0.9700 = 6.5016

H = 8.8000 / 0.9700 = 9.0722

O = 0.9700 / 0.9700 = 1

4. Round up the values to the whole number

C = 7

H = 9

O = 1

5 Write out the empirical formula for the compound

C7H90

In conclusion, the empirical formula for the unknown compound is therefore C7H9O

7 0
3 years ago
The density of solid cu is 8.96 g/cm3. how many atoms are present per cubic centimeter of cu?
svp [43]
Since there is 9.47 x 1021 atoms of copper in 1 gram, and 8.96 grams/cc is the density of copper, then 9.47 x 8.96 =84.85 x 1021 atoms of copper in the one cubic centimeter of copper.
3 0
3 years ago
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