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Elza [17]
3 years ago
6

Diane is able to dissolve 25g of coffee whitener in 250mL of 30°C water before it reaches saturation point. What is the solubili

ty of the coffee whitener at 30°C?
Chemistry
1 answer:
irga5000 [103]3 years ago
6 0

Answer:

i think it is 13

Explanation:

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Consider the reaction H2(g) + I2(g) Double headed arrow. HI(g) with an equilibrium constant of 46.3 and a reaction quotient of 5
Alika [10]

Answer:

The reaction shifts to the left.

Explanation:

Equilibrium constant (K) = 46.3

Reaction Quotient (Q) = 525

The relationship between Q and K with their implications are given as;

K = Q (No net reaction)

K > Q (Reaction shifts to the right)

K < Q (Reaction shifts to the left)

Since in this question, Q (525) > K (46.3)

The reaction shifts to the left.

5 0
2 years ago
Someone please help me with the two I got wrong
LenKa [72]

Answer:

yes

Explanation:

8 0
2 years ago
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The production of iron and carbon dioxide from iron(iii) oxide and carbon monoxide is an exothermic reaction. which expression c
NARA [144]
Missing question:
A. [3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s)] / 2 
<span>B. 3.40 mol Fe2O3 (s) × 26.3 kJ/1 mol Fe2O3 (s) </span>
<span>C. 26.3 kJ/1 mol Fe2O3 (s) / 3.40 mol Fe2O3 (s) </span>
<span>D. 26.3 kJ/1 mol Fe2O3 (s) – 3.40 mol Fe2O3 (s).
</span>Answer is: B.
Chemical reaction: F<span>e</span>₂O₃<span>(s) + 3CO(g) → 2Fe(s) + 3CO</span>₂<span>(g);</span>ΔH = <span>+ 26.3 kJ.
When one mole of iron(III) oxide reacts 26,3 kJ of energy is required and for 3,2 moles of iron(III) oxide 3,2 times more energy is required.</span>
8 0
3 years ago
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How many moles are there in 990 grams of sugar, C12H22011? (Sig Figs, do not
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Answer:

Number of moles = 2.89 mol

Explanation:

Given data:

Number of moles of sugar  = ?

Mass of sugar = 990 g

Solution:

Formula:

Number of moles = mass/molar mass

Molar mass of C₁₂H₂₂O₁₁:

12× 12 + 22×1.008 + 16×11 = 342.2 g/mol

Number of moles = 990 g / 342.2 g/mol

Number of moles = 2.89 mol

6 0
3 years ago
1) 8700cm = ______ km
mart [117]

1. 0.087

2. 0.534

3. 1210000

4. 540

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