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3 years ago

Looking at the structure of caffeine, explain why it is very soluble in a non-polar solvent and a little soluble in water.

1 answer:

7 0

Because in caffeine the don’t use that much soluble in caffeine bis cause then there would be no flavor of caffeine but in water they do so the water doesn’t affect other to stop the solvent from getting stuck.

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A cube of butter weighs .254 pounds and has a volume of 129.4 milliliters what is the density

ira [324]

Density = Mass/Volume

d = .254/129.4

4 0

3 years ago

Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)

spin [16.1K]

Answer: Copper is getting oxidized and is a reducing agent. Silver is getting reduced and is oxidizing agent.

Explanation:

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

$X\rightarrow X^{n+}+ne^-$

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

$X^{n+}+ne^-\rightarrow X$

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

For the given chemical reaction:

$Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)$

The half reactions for the above reaction are:

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$

Reduction half reaction: $2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)$

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.

Silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.

4 0

3 years ago

Read the excerpt from "The Speech."

Y_Kistochka [10]

Answer:

it's quickly moved

Explanation:

whisk

/(h)wisk/

Learn to pronounce

verb

past tense: whisked; past participle: whisked

take or move (someone or something) in a particular direction suddenly and quickly.

Hope this helps ^^

5 0

3 years ago

Read 2 more answers

A solution is prepared by mixing 250 mL of 1.00 M CH3COOH with 500 mL of 1.00 M NaCH3COO. What is the pH of this solution? (Ka f

Svetllana [295]

Answer:

A solution is prepared by mixing 250 mL of 1.00 M

CH3COOH with 500 mL of 1.00 M NaCH3COO.

What is the pH of this solution?

(Ka for CH3COOH = 1.8 × 10−5 )

Explanation:

This is a case of a neutralization reaction that takes place between acetic acid, CH 3 COOH , a weak acid, and sodium hydroxide, NaOH , a strong base.

The resulting solution pH, depends if the neutralization is complete or not. If not, that is, if the acid is not completely neutralized, a buffer solution containing acetic acid will be gotten, and its conjugate base, the acetate anion.

It's important to note that at complete neutralization, the pH of the solution will not equal 7 . Even if the weak acid is neutralized completely, the solution will be left with its conjugate base, this is the reason why the expectations of its pH is to be over 7 .

So, the balanced chemical equation for this reaction is the ionic equation:

CH 3 COOH (aq] + OH − (aq] → CH 3 COO − (aq] + H 2 O (l]

Notice that:

1 mole of acetic acid will react with: 1 mole of sodium hydroxide, shown here as hydroxide anions, OH − , to produce 1 mole of acetate anions:

CH 3 COO −

To determine how many moles of each you're adding , the molarities and volumes of the two solutions are used:

c = n / V ⇒ n = c ⋅ V

n acetic = 0.20 M ⋅ 25.00 ⋅ 10 − 3 L = 0.0050 moles CH3 COOH

and

n hydroxide = 0.10 M ⋅ 40.00 ⋅ 10 − 3 L = 0.0040 moles OH −

There are fewer moles of hydroxide anions, so the added base will be completely consumed by the reaction.

As a result, the number of moles of acetic acid that remain in solution is:

n acetic remaining = 0.0050 − 0.0040 = 0.0010 moles

The reaction will also produce 0.0040 moles of acetate anions.

This is, then a buffer and the Henderson-Hasselbalch equation is applied to find its pH :

pH = p K a + log ( [ conjugate base ] / [ weak acid ] )

Use the total volume of the solution to find the new concentrations of the acid and of its conjugate base .

V total = V acetic + V hydroxide

V total = 25.00 mL + 40.00 mL = 65.00 mL

Thus the concentrations will be :

[ CH 3 COOH ] = 0.0010 moles / 65.00 ⋅ 10 − 3 L = 0.015385 M

and

[ CH 3 COO − ] = 0.0040 moles / 65 ⋅ 10 − 3 L = 0.061538 M

The p K a of acetic acid is equal to 4.75

Thus the pH of the solution will be:

pH = 4.75 + log ( 0.061538 M / 0.015385 M )

pH = 5.35

5 0

3 years ago

Read 2 more answers

Carly lives in an area with temperatures that are always very warm. Carly also lives in an area that is close to the equator. Wh

mariarad [96]

The answer would be B.

hope this helps,

Trey

3 0

3 years ago