First solve the mass of 37.9 L seawater
M = 37.9 L ( 1000 ml / 1L ) ( 1.03 g / ml)
M = 39037 g
Then convert it to lb
M = 39037 g ( 1 lb / 453.592 g)
M = 86.06 lb
<span>Total weight = 86.06 lb + 59.5 lb = 145.56 lb so it can
support the aquarium</span>
Answer is: MgF₂, magnesium fluoride.
Magnesium fluoride is salt, ionic compound, because magnesium is metal from 2. group of Periodic table of elements and has low ionisation energy and electronegativity, which means it easily lose valence electons, fluorine is nonmetal with greatest electronegativity, which meand it easily gain electron, so magnesium cation (Mg²⁺) and fluorine anion (F⁻) are formed.
You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid. So, I would say maybe oil.
