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4 years ago

Which statement is true for electric field lines?

Physics

2 answers:

KiRa [710]4 years ago

8 0

The best answer is D. field lines should always be crossing each other.

yawa3891 [41]4 years ago

3 0

The correct statement is

Field lines should always be perpendicular to the equipotential lines.

we know that, along equipotential lines, work done in moving a charge is zero. Since work done is zero, the force on the charge must be perpendicular to the displacement. the electric force on a charge is parallel to the direction of electric field. hence the electric field must be perpendicular to the displacement or equipotential lines.

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Is power a vector quantity

Morgarella [4.7K]

Answer:

Power is a scalar quantity and has a unit,a magnitude(a numerical value) but no direction.

Explanation:

7 0

3 years ago

A plane leaves the airport in Galisteo and flies 170 km at 68.0° east of north; then it changes direction to fly 230 km at 36.0°

luda_lava [24]

Answer:

The direction will be $84.86^\circ$ and the distance 250.75km.

Explanation:

Let's say A is the displacement vector which represents the first 170km and B the one for the next 230km. Then the components of these vector will be:

$A_x=170cos(68^{\circ})\\ A_y=170sin(68^\circ)\\\\B_x=230cos(-36^\circ)\\B_y=230sin(-36^\circ)$

The vector which point from the origin to the final position of the plane will be R=A+B. We sum components on <em>x </em>and <em>y </em>independetly (vector property):

$R_x=A_x+B_x=170cos(68^{\circ})+230cos(-36^\circ)=63.68km+186.07km=249.75km$

$R_y=A_y+B_y=170sin(68^\circ)+230sin(-36^\circ)=157.62km-135.19km=22.43km$

If $\theta$ is the direction of R then:

$tan(\theta )=\frac{R_x}{R_y}$ ⇒ $\theta = arctan(\frac{R_x}{R_y})$ ⇒ $\theta = 84.86^\circ$ .

The distance will be given by the magnitud of the vector R:

$R=\sqrt{R_x^2 + R_y^2}$ ⇒ $R=\sqrt{R_x^2 + R_y^2} = 250.75$ .

4 0

4 years ago

Sandy is on a road trip. She leaves at 8:00 AM. It takes her 2 hours to drive 200 kilometers. She stops at a rest stop for half

lutik1710 [3]

The average velocity of Sandy is given by the total distance covered S divided by the total time taken t:
$v= \frac{S}{t}$

The total distance covered is
$S=200 km+0+100 km=300 km$
while the total time taken is 2 hours + half an hour (for the rest) + 1 hour and half, so
$t=2h+0.5h+1.5 h=4 h$
Therefore, the average velocity is
$v= \frac{S}{t}= \frac{300 km}{4 h}=75 km/h$

0 0

3 years ago

Can help slow down or stop the motion of an object

matrenka [14]

Net force can help slow down or stop the motion of an object.

6 0

3 years ago

HELP ME PLEASE

tino4ka555 [31]

Answer:

The answer is C. Its not on mars and its not 10 football feilds its only 1

3 0

3 years ago