Answer: 3P/2
Explanation: Let the resistance of the bulbs be R.
now lets consider a Voltage V is supplied to the parallel circuit such that
![P=VI=V^2/R](https://tex.z-dn.net/?f=P%3DVI%3DV%5E2%2FR)
V=IR
both single bulb( bulb 3) and the two bulbs ( bulb 1 and bulb 2) are provided the same Voltage
( as the voltage remains same in parallel circuit)
we can calculate the Current across both circuits
At Bulb 3
Current 1=V/R
Power1=Voltage * Current1
Power1=V*V/R
Power1=P
At Bulb 1 and Bulb 2
Total Resistance= R+R=2R
![Current2=\frac{V}{2R}](https://tex.z-dn.net/?f=Current2%3D%5Cfrac%7BV%7D%7B2R%7D)
Power2=Voltage * Current2
![Power2=V*\frac{V}{2R} \\Power2=\frac{V^2}{2R} \\Power2=P/2](https://tex.z-dn.net/?f=Power2%3DV%2A%5Cfrac%7BV%7D%7B2R%7D%20%5C%5CPower2%3D%5Cfrac%7BV%5E2%7D%7B2R%7D%20%5C%5CPower2%3DP%2F2)
![TotalPower=Power1+Power2\\TotalPower=P+P/2\\TotalPower=\frac{3P}{2}](https://tex.z-dn.net/?f=TotalPower%3DPower1%2BPower2%5C%5CTotalPower%3DP%2BP%2F2%5C%5CTotalPower%3D%5Cfrac%7B3P%7D%7B2%7D)
<span>To begin, the mouse walks from 5 to 12 cm, for a displacement of 7 cm. Next, it walks 8 cm in the opposite direction, for a total displacement of (7 + [-8]) or (-1) cm. This leaves the mouse on 4 cm, and then it walks from there to the 7cm location, for a displacement of 7-4 or +3 cm. Adding 3cm to -1cm gives a final displacement of +2cm.</span>
That would be an asteroid
We don't know the change in velocity, so can't answer.