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disa [49]
3 years ago
9

HELLPP DUE TODAY ONLY 2 questions!!!!! WILL MARK YOU BRAINLIST AND 20 points

Chemistry
1 answer:
mihalych1998 [28]3 years ago
7 0

Explanation:

2CO (g) + O2 (g) → 2CO2 (g) ∆H = –566.0 kJ exothermic

2SO2(g) + O2(g) <=> 2SO3(g). Delta H = -198.2 kJ/mol. exothermic

You might be interested in
Sodium is a larger atom than lithium. List three reasons why this is true.
just olya [345]

Answer:

It is present in third period that's why its valance electrons are present in 3rd energy level.

Its atomic number is greater than lithium when compared in group wise.

There are more electrons in sodium to shield the outer valance electron thus nuclear attraction becomes weak and size increase.

Explanation:

The size of sodium is greater than lithium because atomic number of sodium is 11 and lithium is 3. Both are present in first group but sodium is present down to the lithium. As we move from top to bottom in a group atomic size increases with addition of electrons. The nuclear effect become weaker on valance electrons and atomic size increase. Same time shielding effect is also produces which shield the outer electrons from the influence of nucleus. While in case of lithium less electrons are present to shield the valance electrons.

As we note the position of both elements along period. The sodium is present in third period while lithium is present in second period. So, in case of sodium third energy level is involved. That's why its size is greater than lithium.

8 0
3 years ago
If the equilibrium constant for the reaction A 2B C 5/2 D has a value of 4.0, what is the value of the equilibrium constant for
nirvana33 [79]

Answer:

K'=\frac{1}{16}

Explanation:

Hello!

In this case, since the given reaction is:

A+ 2B \rightleftharpoons C+ \frac{5}{2} D

Whereas the equilibrium constant is:

K=\frac{[C][D]^{5/2}}{[A][B]^2} =4.0

However, the new target reaction reverses and doubles the initial reaction to obtain:

2C+5D \rightleftharpoons 2A+4B

Whereas the equilibrium constant is:

K'=\frac{[A]^2[B]^4}{[C]^2[D]^5}

Which suggest the following relationship between the equilibrium constants:

K'=\frac{1}{K^2}

So we plug in to obtain:

K'=\frac{1}{4.0^2}\\\\K'=\frac{1}{16}

Best regards!

8 0
3 years ago
Which is the correct way to write 602,200,000,000,000,000,000,000 in scientific notation?
sladkih [1.3K]

Answer:

6.022 x 10^23

Explanation:

There are 20 zeros and the 022 are 3 more places.

3 0
4 years ago
For the following reaction, 35.4 grams of zinc oxide are allowed to react with 6.96 grams of water . zinc oxide(s) + water(l) --
IRISSAK [1]

Answer:

m_{Zn(OH)_2}=38.4g

Explanation:

Hello!

In this case, for the undergoing chemical reaction:

ZnO(s)+H_2O(l)\rightarrow Zn(OH)_2

We evaluate the yielded moles of zinc hydroxide by each reactant as shown below:

n_{Zn(OH)_2}^{by ZnO}=35.4gZnO*\frac{1molZnO}{81.38gZnO}*\frac{1molZn(OH)_2}{1molZnO}  =0.435molZn(OH)_2\\\\n_{Zn(OH)_2}^{by H_2O}=6.96gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{1molZn(OH)_2}{1molH_2O}  =0.386molZn(OH)_2

In such a way, since the water yields a smaller amount of zinc hydroxide we conclude it is the limiting reactant so the maximum mass is computed below:

m_{Zn(OH)_2}=0.386molZn(OH)_2*\frac{99.424 gZn(OH)_2}{1molZn(OH)_2} \\\\m_{Zn(OH)_2}=38.4g

Because the water limits the yielded amount of zinc hydroxide.

Best regards!

5 0
3 years ago
A 0.2 M carboxylic acid (RCOOH) has a Ka = 1.66x10-6. What is the pH of this solution? Enter to 2 decimal places.
maria [59]

Answer:

3.24

Explanation:

The dissociation equation for the carboxylic acid can be represented as follows:

RCOOH —-> RCOO- + H+

We can use an ICE table to get the value of the concentration of the hydrogen ion. ICE stands for initial, change and equilibrium.

RCOOH RCOO- H+

Initial 0.2 0.0. 0.0

Change -x +x. +x

Equilibrium 0.2-x. x. x

We can now find the value of x as follows:

Ka = [RCOO-][H+]/[RCOOH]

(1.66* 10^-6) = (x * x)/(0.2-x)

(1.66 * 10^-6) (0.2-x) = x^2

x^2 = (3.32* 10^-7) - (1.66*10^-6)x

x^2 + (1.66 * 10^-6)x - (3.32* 10^-7) = 0

Solving the quadratic equation to get x:

x = 0.0005753650094369094 or - 0.0005753650094369094

As concentration cannot be negative, we discard the negative answer

Hence [H+] = 0.0005753650094369094

By definition, pH = -log[H+]

pH = -log(0.0005753650094369094)

pH = 3.24

8 0
3 years ago
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