All categories

3 years ago

Salt is a homogeneous or heterogeneous mixture and why?

Chemistry

1 answer:

Wittaler [7]3 years ago

8 0

Explanation:

A mixture in which its constituents are distributed uniformly is called homogeneous mixture, such as salt in water. A mixture in which its constituents are not distributed uniformly is called heterogeneous mixture, such as sand in water.

You might be interested in

If an endothermic reaction occurs in solution, the temperature of the solution will

Ahat [919]

Answer:

increase

Explanation:

because in endothermic reaction heat is absorbed

4 0

3 years ago

The thermometer in the picture reads, "19.9 degrees Celsius".

GalinKa [24]

Answer:

Sorry but i can't help

Explanation:

i need to really finesh s

6 0

3 years ago

A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m

aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( $q_{\ lost}$ )= heat absorbed by the less hotter sample( $q_{\ gain}$ )

The relationship between heat (q), mass (m) and temperature (t) is $q = mc\Delta t$

where c is specific heat capacity, $\Delta t$ temperature change.

$\Delta t$ = $t_{\ final} - t_{\ initial}$

equating both heat emitted and absorb

$-q_{\ lost} = q_{\ gain}$

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * ( $t_{final}$ - 330) = 30 * ( $t_{final}$ - 280)

-50 $t_{final}$ + 16500 = 30 $t_{final}$ - 8400

80 $t_{final}$ = 16500+8400

80 $t_{final}$ = 24900

$t_{final}$ = 24900/80 = 311.25k

8 0

3 years ago

A balloon has a pressure of 3.1 atm at a volume of 155 ml. if the temperature is held constant, what is the volume (ml) if the p

GarryVolchara [31]

Answer:

45.8 mL

Explanation:

If all variables are held constant, the new volume can be found using the Boyle's Law equation. The equation looks like this:

P₁V₁ = P₂V₂

In this equation, "P₁" and "V₁" represent the initial pressure and volume. "P₂" and "V₂" represent the final pressure and volume. You can find the new volume by plugging the given values into the equation and simplifying.

P₁ = 3.1 atm P₂ = 10.5 atm

V₁ = 155 mL V₂ = ? mL

P₁V₁ = P₂V₂ <----- Boyle's Law equation

(3.1 atm)(155 mL) = (10.5 atm)V₂ <----- Insert values

480.5 = (10.5 atm)V₂ <----- Multiply 3.1 and 155

45.8 = V₂ <----- Divide both sides by 10.5

4 0

2 years ago

Explain why iron structures need protection from corrosion while aluminium structures do not?

KiRa [710]

<span>Because aluminium oxide is strong and forms a coating over itself, but iron oxide (rust) will flake away.</span>

4 0

3 years ago