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asambeis [7]
3 years ago
12

Why is the average atomic mass used when calculating grams of a

Chemistry
2 answers:
olga55 [171]3 years ago
6 0

Answer:

B. The elements in the substance are mixtures of their isotopes.

Lera25 [3.4K]3 years ago
4 0
I guess the answer is B
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An example of a solution is vinegar because it has 5% acid and 95% water True orFalse​
Blababa [14]

Answer:

The answer is true!

Explanation:

8 0
4 years ago
Initial Concentration mol/L[A] Initial Concentration mol/L[B] Initial Rate mol/Ls 0.20 0.10 20 0.20 0.20 40 0.40 0.20 160 Given
zimovet [89]
The generalized rate expression may be written as:
r = k[A]ᵃ[B]ᵇ

We may determine the order with respect to B by observing the change in rate when the concentration of B is changed. This can be done by comparing the first two runs of the experiment, where the concentration of A is constant but the concentration of B is doubled. Upon doubling the concentration of B, we see that the rate also doubles. Therefore, the order with respect to concentration of B is 1.
The same can be done to determine the concentration with respect to A. The rate increases 4 times between the second and third trial in which the concentration of B is constant, but that of A is doubled. We find that the order with respect to is 2. The rate expression is:

r = k[A]²[B]
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3 years ago
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liubo4ka [24]

Answer:

Pascal is the most common unit for measuring pressure

The average sea level pressure is 1013 mbar

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Why don't the particles in a solid move past one another?
zlopas [31]

Answer:

the attractive forces keep the particles together tightly enough so that the particles do not move past each other.

Explanation:

In the solid the particles vibrate in place.

7 0
3 years ago
Calculate the standard molar enthalpy of formation, in kJ/mol, of NO(g) from the following data:
Paraphin [41]

The above question is incomplete, here is the complete question:

Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o= -114.1 kJ

Answer:

The standard molar enthalpy of formation of NO is 90.25 kJ/mol.

Explanation:

N_2(g) + 2O_2 \rightarrow 2NO_2(g), \Delta H^o_{1} = 66.4 kJ

2NO(g) + O_2\rightarrow 2NO_2(g),\Delta H^o_{2} = -114.1 kJ

To calculate the standard molar enthalpy of formation

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?...[3]

Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

[1] - [2] = [3]

N_2+O_2\rightarrow 2NO(g),\Delta H^o_{3} = ?

\Delta H^o_{3} =\Delta H^o_{1} - \Delta H^o_{2}

\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ

According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :

=\frac{\Delta H^o_{3}}{2 mol}

=\frac{180.5 kJ}{2 mol}=90.25 kJ/mol

3 0
3 years ago
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