Alkenes undergo
Electrophillic Addition Reactions. Electrophiles are added across double bond. In given reaction the
H⁺ is first added across double bond as the double bond being denser in electron density act as a neucleophile. A
carbocation formed depends upon the nature of Alkene, if alkene is
symmetrical (as in our case) then positive charge can get any position, but in case of
unsymmetrical alkene the positive charge will go to that carbon which is attached to more carbon atoms. Then the water molecule attacks the carbocation and forms
alcohol.
There are 1.16x10²² sulfide <em>ions </em>(S²⁻) in 15 dg of sodium sulfide (Na₂S).
The equation for sodium sulfide is the following:
Na₂S → 2Na⁺ + S²⁻ (1)
So from equation (1), we can see that in<u> 1 mol</u> of <em>sodium sulfide</em> we have <u>1 mol</u> of <em>sulfide ions</em> and 2 moles of sodium ions.
First, let's find the number of moles of<em> Na₂S</em>
(2)
Where:
: is the mass of Na₂S = 15 dg = 1.5 g
: is the molar mass of Na₂S = 78.0452 g/mol
The <em>number of moles</em> of Na₂S is (eq 2):
We can find the number of ions of S²⁻ with Avogadro's number, knowing that the number of moles of Na₂S is equal to the number of moles of S²⁻ (eq 1).
Therefore, there are 1.16x10²² sulfide <em>ions </em>in 15 dg of sodium sulfide.
Find more about Avogadro's number here:
I hope it helps you!
Answer:
Explanation:
Here, we want to write the chemical reaction
step 1:
we start by writing the reaction between iron and oxygen
We have this as:
step 2:
Now, we want to predict the product as follows:
step 3:
We proceed to balance the chemical reaction as follows by ensuring that the number of elements moles on the reactant side is equal to the number of moles of the elements on the products side as follows:
Answer:
5.71 x 1021 (C)
Explanation:
Because if the numbers are over 5 then u round to the next number. So since 6 is bigger than 5 that means is gonna round up so it will be 7 and so. I hope that helps a bit