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Georgia [21]
3 years ago
11

Solve for the value of x in this equation: -10x+17x-2 = 5(x+4)

Mathematics
2 answers:
Basile [38]3 years ago
4 0

Answer:

\huge{ \bold{ \boxed{ \tt{x = 11}}}}

Step-by-step explanation:

\text{ - 10x + 17x - 2 = 5(x + 4)}

Subtract 10x from 17x

10x and 17x are like terms. So, the coefficients of like terms can be added or subtracted.

\dashrightarrow{ \sf{ 7x - 2 = 5(x + 4)}}

Distribute 5 through the parentheses

\dashrightarrow{ \sf{7x - 2 = 5 \times x  + 5 \times 4}}

\dashrightarrow{ \sf{7x - 2 = 5x  +  20}}

Move 5x to left hand side ( L.H.S ) and change it's sign

Similarly , move 2 to right hand side ( R.H.S ) and change it's sign

\dashrightarrow{ \sf{7x - 5x =   20 + 2}}

Subtract 5x from 7x

\dashrightarrow{ \sf{2x =  20 + 2}}

Add the numbers : 20 and 2

\dashrightarrow{ \sf{2x = 22}}

Divide both sides by 2

\dashrightarrow{ \sf{ \frac{2x}{2}  =  \frac{22}{2}}}

\dashrightarrow{ \boxed{ \sf{x = 11}}}

--------------------------------------------------------------

Now, let's check whether the value of x is 11 or not.

<h3>Verification :</h3>

L.H.S = n\sf{ - 10x + 17x - 2}

Plug the value of x and simplify

\longrightarrow{ \sf{ - 10 \times 11 + 17 \times 11 - 2}}

\longrightarrow{ \sf{ - 110 + 187 - 2}}

\longrightarrow{ \sf{77 - 2}}

\dashrightarrow{ \sf{75}}

R.H.S = \sf{5(x + 4)}

plug the value of x and simplify

\longrightarrow{ \sf{5(11 + 4)}}

\longrightarrow{ \sf{5 \times \: 15}}

\longrightarrow{ \sf{75}}

L.H.S = R.H.S

The value of x is 11 .

--------------------------------------------------------------

<h3>Rules for solving an equation :</h3>
  • If an equation contains fractions , multiply each term by the LCM of denominators.
  • Remove the brackets , if any.
  • Collect the terms with the variable to the left hand side and constant terms to the right side by changing their signs ' + ' into ' - ' and ' - ' into ' + '
  • Simplify and get the single term on each side.
  • Divide each side by the coefficient of variable and then get the value of variable.

Hope I helped!

Best regards :D

~\text{TheAnimeGirl}

zepelin [54]3 years ago
3 0
Ok here are the steps and the answer

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<h3>Answer:</h3>

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<h3>Step-by-step explanation:</h3>

Get the area of the tiles

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8,500/70

121.428571

Round up

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Step-by-step explanation:

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Step-by-step explanation:


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3 years ago
The points (x, 3) and (-2, 2) have a slope of 1. What is the x-coordinate of the point<br> (x, 3)?
Naya [18.7K]

Answer:

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Step-by-step explanation:

The slope is given by

m = (y2-y1)/(x2-x1)

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Multiply by -1

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7 0
3 years ago
Large samples of women and men are​ obtained, and the hemoglobin level is measured in each subject. Here is the​ 95% confidence
qwelly [4]

Answer:

a) Because the confidence interval  does not include  0​ it appears that there

is  a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.

b)There is​ 95% confidence that the interval from  −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2

c)   1.62 < μ1−μ2< 1.76

Step-by-step explanation:

a) What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in​ men?

Given:

95% confidence interval for the difference between the two population​ means:

−1.76g/dL< μ1−μ2 < −1.62g/dL

population 1 =  measures from women

population 2 =  measures from men

Solution:

a)

The given confidence interval has upper and lower bound of 1-62 and -1.76. This confidence interval does not contain 0. This shows that the population means difference is not likely to be 0. Thus the confidence interval implies that the mean hemoglobin level in women and the mean hemoglobin level in​ men is not equal and that the  women are likely to have less hemoglobin than men. This depicts that there is significant difference between mean hemoglobin level in women and the mean hemoglobin level in​ men.

b)  

There is​ 95% confidence that the interval −1.76 g/dL<μ1−μ2<−1.62 g/dL actually contains the value of the difference between the two population means μ1−μ2.

c)

If we interchange men and women then

  • confidence interval range sign will become positive.
  • μ1 becomes the population mean of the hemoglobin level in men
  • μ2 becomes the population mean of the hemoglobin level in women
  • So confidence interval becomes:

                                          1.62 g/dL<μ1−μ2<1.76 g/dL.

4 0
2 years ago
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