∠BDC and ∠AED are right angles, is a piece of additional information is appropriate to prove △ CEA ~ △ CDB
Triangle AEC is shown. Line segment B, D is drawn near point C to form triangle BDC.
<h3> What are Similar triangles?</h3>
Similar triangles, are those triangles which have similar properties,i.e. angles and proportionality of sides.
Image is attached below,
as shown in figure
∡ACE = ∡BCD ( common angle )
∡AED = ∡BDC ( since AE and BD are perpendicular to same line EC and make right angles as E and C)
∡EAC =- ∡DBC ( corresponding angles because AE and BD are parallel lines)
Thus, △CEA ~ △CDB , because of the two perpendiculars AE and BD.
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Answer:
Third item in the list
Step-by-step explanation:
Third function: f(x) = x + 9. If we substitute 14 for x, we get f(14) = 14 + 9 = 23.
Step-by-step explanation:
118 is the answer 238-120 = 118
Answer:
-2x + 2
Step-by-step explanation:
you didn't post choices but combining like terms you get
-2x + 2