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nirvana33 [79]
3 years ago
7

Find the area of each circle. Round to the nearest tenth. Use 3.14 for π.

Mathematics
1 answer:
joja [24]3 years ago
3 0

Answer:

1. 490.6 mm²

2. 14.1 ft²

Step-by-step explanation:

1. 3.14×(12.5)²= 3.14 × 156.25 =490.6mm²

2. ½×3.14×3²= 3.14×4.5= 14.1 ft²

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wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Can someone explain how to do #3?
dsp73

\displaysyle (\sqrt 2)^{3}=(2^{\frac{1}{2}})^3=2^{\frac{1}{2} \cdot 3}=2^{\frac{3}{2}}=\sqrt {2^3}=\sqrt 8

√8 is between 2 and 3, because 2²=4<8, but 3²=9>8. Also, our value is closer to 3 than to 2, so it is more than 2.5 and we have C and D options left.

Among these two numbers we find the one which is closer to √8.

C. 27=√729 ⇒ 2.7=√7.29

D. 28=√784 ⇒ <u>2.8=√7.84</u>

Hence our answer is D) 2.8

5 0
4 years ago
Read 2 more answers
Derivative of y= 2^(sin pi x)
laila [671]
Take log of both sides
\ln y = \ln(2^{\sin \pi x})
Use log property to get "x" out of the exponent
\ln y = (\ln 2) (\sin \pi x)
Differentiate
\frac{dy}{y} = (\pi \ln 2)(cos \pi x) dx
Move y to Right side  (Note y = original expression)
\frac{dy}{dx} = (\pi \ln 2) (\cos \pi x) 2^{\sin \pi x}

In general, whenever you have a function in the form
y = a^{f(x)}
The derivative will be
\frac{dy}{dx} = (\ln a) (f'(x))a^{f(x)}
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3 years ago
1/4 m = 6 <br><br> what is m?
topjm [15]

Answer:

24

Step-by-step explanation: 6 divided by 1/4 is 24

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4 years ago
Ranjit has six coins in his pocket.
mash [69]

Step-by-step explanation:

=$-383-3"jsjsbbshs sjusiwbw wuuiwn

8 0
3 years ago
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