All categories

3 years ago

Lines that appear to be tangent are tangent. Find the value of each variable.

Mathematics

1 answer:

galina1969 [7]3 years ago

4 0

Tangent secant theorem which in this case says

6² = x (x + x) = 2x²

36 = 2x²

18 = x²

x = 3√2

Answer: x = 3√2

You might be interested in

Which equation best represents this situation? The number 88 is equal to a number divided by 11. A. 88 = 11g B. 88 = 11 + g C. 8

miv72 [106K]

The answer is D. 88=g/11

4 0

3 years ago

Read 2 more answers

A tree that is next to a telephone pole is 15 feet tall and casts a shadow 4 feet long.

alekssr [168]

Answer:

24ft is the length of the shadow of the telephone pole

Step-by-step explanation:

Well first what I did was divide 15 by 4 which equaled to 3.75, after that the question said that the telephone pole was now 90 feet tall so I just had to divide 90 by 3.75 and then 24 ft long was the final answer. I hope that helps

4 0

2 years ago

Simplify √ 105 A. 2√ 7 B. √ 42 C. 2√ 3 D. √ 105

IrinaVladis [17]

√105 is written in simplest form already.

The answer would be D. √105

7 0

3 years ago

Aurora hit a baseball with an initial velocity of 70 feet per second at an angle of 30° with the horizontal. The ball hit her ba

snow_tiger [21]

Answer:

See below

Step-by-step explanation:

Y component of velocity is 70 sin 30°

y position = 3 + 70 sin 30° * t - 1/2 a t^2

when the ball hits the ground y = 0

0 = 3 + 70 sin 30° t - 1/2 (32.2)t^2

- 16.1 t^2 + 35t + 3 = 0

Use Quadratic Formula to find t = 2.26 seconds

Horizontal component of initial velocity

70 cos 30° distance horizontal = 70 cos 30° * t

= 70 cos 30° (2.26) = 137.0 ft

4 0

2 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

Hence, the second term is 200

5 0

3 years ago