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Kipish [7]
3 years ago
14

What is the relationship between electric field lines and equipotential lines that you observed in doing the lab

Physics
1 answer:
lidiya [134]3 years ago
8 0

Answer:

Explained below

Explanation:

Generally speaking, we know in physics that Electric field lines are lines which usually start at positive charges and deflect away from them to terminate at the negative charges. Meanwhile Equipotential lines are lines that are used to connect points located on the same electric potential.

Finally, in conclusion, electric field lines are usually lines that go through in a perpendicular manner across every equipotential lines.

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What is the velocity of a plane that traveled 3,000 miles from new york to california in 5.0
ad-work [718]
You have to divide 3000 miles with the 5 and it gives you a velocity of 600 
4 0
3 years ago
A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial tempe
Taya2010 [7]

Complete question:

A 3.53-g lead bullet traveling at 428 m/s strikes a target, converting its kinetic energy into thermal energy. Its initial temperature is 40.0°C. The specific heat is 128 J/(kg · °C), latent heat of fusion is 24.5 kJ/kg, and the melting point of lead is 327°C.

(a) Find the available kinetic energy of the bullet. J

(b) Find the heat required to melt the bullet. J

Answer:

Part (a) the available kinetic energy of the bullet is 323.32 J

Part (b) the heat required to melt the bullet is 216.17 J

Explanation:

Given;

mass of the bullet = 3.53 g = 0.00353 kg

velocity of the bullet = 428 m/s

initial temperature of the bullet = 40.0°C

final temperature of the bullet =  327°C

specific heat capacity, c= 128 J/(kg · °C)

latent heat of fusion, Hf  = 24.5 kJ/kg

Part (a) the available kinetic energy of the bullet. J

KE = ¹/₂ × mv²

KE = ¹/₂ × 0.00353 × 428²

     = 323.32 J

Part (b) the heat required to melt the bullet. J

This is the thermal energy required to increase the temperature of the bullet and the heat energy required to melt the bullet.

Quantity of heat required to raise the temperature of the bullet:

Q = mcΔT

   = 0.00353 × 128 × (327-40)

   = 0.00353 × 128 × 287

   = 129.68 J

Quantity of heat required to melt the bullet:

Q = mH_f

Q = 0.00353 × 24500

   = 86.49 J

TOTAL energy required to melt the bullet = 129.68 J + 86.49 J

                                                                      = 216.17 J

3 0
3 years ago
In which does sound travel fastest? Question 8 options: solids liquids gases plasma.
Kazeer [188]

Sound travels fastest in solids. A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.

<h3>What is sound?</h3>

A sound is a vibration that travels in a longitudinal direction through a medium in the form of a mechanical wave.

It can propagate through a solid, a liquid, or a gas as its medium. Solids go the fastest, liquids are slower, and gases are the slowest.

Sound travels the quickest through a solid because the molecules are packed together densely, allowing sound waves to leap from one molecule to the next more quickly.

Because the molecules in solids are packed the tightest, sound travels the quickest through them, whereas sound travels the slowest through gases.

To learn more about the sound refer to the link;

brainly.com/question/927975

4 0
3 years ago
A pulley system operates with 40% efficiency. if the work put in is 200 joules, how much useful work is produced?
QveST [7]

<span>1.    </span><span>Efficiency is the measure of how efficient a process is. It is used to assess the ability of a process in avoiding waste energy, materials, money and time in doing a desirable output. It is calculated as;

Efficiency = useful energy ouput / total energy input</span>

<span>.40 = useful work / 200</span>

<span>useful work = 80 joules</span>

8 0
4 years ago
Read 2 more answers
A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105m above the Earth, a package is dropped from a w
Luden [163]

Here it is given that initial speed of the package will be same as speed of the helicopter

v_i = 5.10 m/s

displacement of the package as it is dropped on ground

d = -105 m

acceleration is due to gravity

a = -9.8 m/s^2

now by kinematics

y = v* t + \frac{1}{2}at^2

-105 = 5.1 * t - \frac{1}{2}*9.8*t^2

4.9 t^2 - 5.1 t - 105 = 0

by solving above equation we have

t = 5.2 s

so it will take 5.2 s to reach the ground

7 0
3 years ago
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