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Sedaia [141]
4 years ago
14

Why do soundwaves move faster than the ground than through the air​

Physics
1 answer:
Sati [7]4 years ago
8 0

Answer:

Particles of matter are packed more tightly in the ground than in the air

Explanation:

the reason is that sound waves are vibrations of the molecules of the medium: therefore, if the particles of the medium are closer together (as in solids), the vibrations can be transmitted faster, and the wave can travel faster

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A blue car with mass mc = 468 kg is moving east with a speed of vc = 21 m/s and collides with a purple truck with mass mt = 1264
r-ruslan [8.4K]
<span>To calculate the magnitude of the initial momentum of the car in this situation you have to multiple the mass of the blue car times the speed. The mass, 468kg, times the speed, 21 m/s, equals 9828. This means the magnitude of the initial momentum of the blue car in the situation is 9828kg per m/s. In this case, and in simple terminology, the magnitude measures how big something is. So the magnitude of the momentum is just the measurement of how big the initial moment of the car is.</span>
5 0
3 years ago
How are sports related to the concepts of force and motion?
crimeas [40]
Related to the force of motion,
Motion: Ability to move in a way of frequency.
Explanation: When we move in sport our bodies are more prone to motion and kinetic energy.

Hope this help :)
5 0
3 years ago
In the picture below, the candle is heating the water in the tank. Which picture shows how the water will move as it gets hot?
Masteriza [31]

The first picture, at the top, does.

5 0
3 years ago
Read 2 more answers
(1 point) A frictionless spring with a 6-kg mass can be held stretched 0.2 meters beyond its natural length by a force of 50 new
guapka [62]

Answer:

x(t) = 0.077cos(6.455t)

Explanation:

If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:

k = 50 / 0.2 = 250 N/m

The equation of simple harmonic motion is as the following:

x(t) = Acos(\omega t - \phi)

where \omega = \sqrt{k/m} = \sqrt{250 / 6} = 6.455

We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:

v_{max} = A\omega

A = v_{max}/\omega = 0.5 / 6.455 = 0.077 m

\phi = 0 is the initial phase

Therefore, the position of the mass after t seconds is

x(t) = 0.077cos(6.455t)

6 0
3 years ago
Assume that the solar radiation incident on Earth is 1330 W/m2 (at the top of the atmosphere). Find the total power radiated by
Temka [501]

Answer:

The total power radiated by the sun is 3.71×10^26W

Explanation:

The Earth is spherical in shape

Therefore, Area = 4πr^2 = 4×3.143×(1.489×10^11)^2 = 2.79×10^23m^2

Power radiated by the Sun = solar radiation on Earth × Area = 1330W/m^2 × 2.79×10^23m^2 = 3.71×10^26W

8 0
3 years ago
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