The correct answer is
D.
unbalanced forces
In fact, according to Newton's second law, unbalanced forces acting on an object will accelerate the object:
where the term on the left is the resultant of the forces acting on the object, m is the object's mass, and a is its acceleration.
If there are unbalanced forces acting on the object, the acceleration of the object a is different from zero: this means that the object will change its speed or its direction, or it can also stop moving if the direction of the force is opposite to that of the motion.
Should be B I took the same
Answer:
Tension= 21,900N
Components of Normal force
Fnx= 17900N
Fny= 22700N
FN= 28900N
Explanation:
Tension in the cable is calculated by:
Etorque= -FBcostheta(1/2L)+FT(3/4L)-FWcostheta(L)= I&=0 static equilibrium
FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)
Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)
Ftorque= 2/3FBcostheta+ 4/3FWcostheta
Ftorque=2/3(1350)(9.81)cos55° + 2/3(2250)(9.81)cos 55°
Ftorque= 21900N
b) components of Normal force
Efx=FNx-FTcos(90-theta)=0 static equilibrium
Fnx=21900cos(90-55)=17900N
Fy=FNy+ FTsin(90-theta)-FB-FW=0
FNy= -FTsin(90-55)+FB+FW
FNy= -21900sin(35)+(1350+2250)×9.81=22700N
The Normal force
FN=sqrt(17900^2+22700^2)
FN= 28.900N
The electrostatic force between the two charges is
Explanation:
The electrostatic force between two charges is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges
r is the separation between the two charges
In this problem, we have the following data:
is the magnitude of the two charges, where
is the fundamental charge
is the separation between the two charges
Substutiting into the equation, we find the force:
Learn more about electric force:
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