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Angelina_Jolie [31]
3 years ago
7

Please answer question b math help ( please show work )

Mathematics
1 answer:
BartSMP [9]3 years ago
8 0

Answer:

a = 10.9

b = 10.4

Step-by-step explanation:

<u>part a: use sine</u>

⇒ sine = \frac{opposite}{hypotenuse}

⇒ sine 23 = \frac{y}{28}

(sine 23 = 0.39)

⇒ 0.39 = \frac{y}{28}

multiply each side by 28

⇒ 0.39 x 28 = \frac{y}{28} x 28

⇒ 10.9

<u>part b: use cosine</u>

⇒ cos = \frac{adjacent}{hypotenuse}<u />

⇒ cos 29 = \frac{y}{12}

(cos 29 = 0.87)

⇒ 0.87 = \frac{y}{12}

multiply 12 on both sides

⇒ 0.87 x 12 = \frac{y}{12} x 12

⇒ 10.4

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The following is a geometric sequence.<br> - 1/2 , 1/4, -1/8 , 1/16 <br> true <br> false
seraphim [82]

Answer:

True

Step-by-step explanation:

It has a common ratio of -1/2

Each term after the first is obtained by multiplying the previous one by -1/2:-

-1/2 * 1/2 = 1/4 ;  1/4 * -1/2 = -1/8  and so on.

6 0
3 years ago
Use the distributive property to find the equivalent expression<br> 7(8 + d
olchik [2.2K]

Answer:

56 + 7d

Step-by-step explanation:

For using the distributive property, You have to multiply the first number to the rest. So 8 x 7 = 56 and 7 x d = 7d.

4 0
3 years ago
Please help geometry
sveta [45]

Answer:

The answer to your question is 11.4 units

Step-by-step explanation:

Data

A (-3, -1)

B ( 0, 3)

C ( 1, 2)

Perimeter = ?

Formula

d = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

Process

1.- Find the length between the points

dAB = \sqrt{0 + 3)^{2} + (3 + 1)^{2}}

dAB = \sqrt{3^{2}+ 4^{2}}

dAB = \sqrt{9 + 16}

dAB = \sqrt{25}

dAB = 5

dBC= \sqrt{(1 - 0)^{2} + (2 - 3)^{2}}

dBC = \sqrt{1^{2} + (-1)^{2}}

dBC = \sqrt{1 + 1}

dBC = \sqrt{2}

dAC = \sqrt{(1 + 3)^{2} + (2 + 1)^{2}}

dAC = \sqrt{4^{2} + 3^{2}}

dAC = \sqrt{16 + 9}

dAC = \sqrt{25}

dAC = 5

2.- Perimeter

P = AB + BC + AC

P = 5 + \sqrt{2} + 5

P = 10 + \sqrt{2}

P = 10 + 1.42

P = 11.4

7 0
3 years ago
Simplify:<br> 4 x 32 - 3+5x2 = <br> A. 33<br> B. 43<br> C. 36<br> D. 58<br> E. 34
NeX [460]
I got 155‍♀️ I don’t know cause I did PEMDAS and got 155
3 0
3 years ago
Read 2 more answers
EF is tangent to circle P at G (1,-3). If the slope of EF is 7/9, what is the slope of GP?
pentagon [3]
The center of the circle is at P. 
The tangent EF is tangent to the circle at point G. So GP will be the radius of the circle. 

The slope of tangent EF = 7/9

The tangent of a circle is always perpendicular to the radius at the point where it touches the circle. So we can say that EF is perpendicular to GP.

The product of slopes of two perpendicular line is always equal to -1.

Slope of EF x Slope of GP = -1
So,

Slope of GP = - 1 / (Slope of EF)

Thus slope of GP = - 9/7
7 0
3 years ago
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