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3 years ago

Help Now Please!!! Given The Three sides of the triangle?

Mathematics

1 answer:

jeka943 years ago

8 0

Answer:

right angle thats must be the ans

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Which are the x-intercept and y-intercept of the line drawn through the points A and B?

ladessa [460]

First you have to figure out what the equation of the line is. Let's use the slope formula to find the slope, and then one of the points to find the y-intercept. We'll put the line's equation in y=mx+b form.

$slope = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} } \\ slope = m \\ m = \frac{5 - 1}{-7 - 1} \\ m = \frac{4}{-8} \\ m = - \frac{1}{2}$

Now, we'll use that slope in y=mx+b form with one of the coordinates in order to find what b (which is also the y-intercept) equals
$y = - \frac{1}{2}x + b \\ 1 = 1(- \frac{1}{2}) + b \\ 1 = - \frac{1}{2} + b \\ 1 \frac{1}{2} = b$

therefore your y-intercept is equal to 1.5. In order to find the x-intercept we'll take our new equation $y = - \frac{1}{2} + 1 \frac{1}{2}$ and make y = 0, because the line intersects with the x-axis when y is equal to zero.

$y = - \frac{1}{2}x + 1 \frac{1}{2} \\ 0 = - \frac{1}{2}x + 1 \frac{1}{2} \\ -1 \frac{1}{2} = - \frac{1}{2}x \\ x = 3$

therefore, your x-intercept is 3 and your y-intercept is 1.5

6 0

3 years ago

Answer ASAP please

Vikki [24]

Answer:

h = 16 || solution after squaring: $x = -0.683$ or $x = -7.32$

steps by fieranswererft:

Given: $x^2+8x+5=0$

Take half of the x term and square it

$[8*\frac{1}{2} ]^2=16$

$x^2+8x+16=- 5+16$

$(x+4)^2=-5+16$

$(x+4)^2=11$

$x+4 = \pm \sqrt{11}$

$x = \pm \sqrt{11}-4$

$x = -0.683$ or $x = -7.32$

7 0

3 years ago

For the problem 135/5, draw two different ways to break apart the array. Use the Distributive property to write products for eac

GrogVix [38]

5×135? Distributive Property? 135 rounds to 100 and 200 5×1=5 5 and add 00 is 500 5×2=10 10 and add two 00's is 1000 the answer is in between 500 and 1000

6 0

3 years ago

With the beam being held still at a height of 40 m, the crane breaks and the beam falls to the ground. Assuming no air resistanc

lapo4ka [179]

What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.

Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy

TE = 0 + 0

∴ TE = 0

The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.

8 0

3 years ago

PLEASE HELP, IT WOULD BE GREAT IF SOMEONE COULD ANSWER QUICKLY AND CORRECTLY!!!!

Dominik [7]

Answer:

5x+2y+z

Step-by-step explanation:

just count all of the variables

5 0

3 years ago

Read 2 more answers