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OleMash [197]
2 years ago
12

Select all that apply.

Chemistry
1 answer:
deff fn [24]2 years ago
5 0

Answer:

backward, opposite, retrograde

Explanation:

why, i just got it right when i put that.

You might be interested in
Which substances were ionic?
horsena [70]
<h3>Sodium chloride  and Sodium bicarbonate are ionic substances</h3><h3>Further explanation </h3>

Atoms have different stability. Unstable atomic atoms will try to form stable electron configurations like those of noble gases. Where noble gases have the number of outer electrons 2 or 8

The formation of electron configurations such as noble gases can be done by sharing electrons with covalent bonds or hand over electrons with ionic bonds

Generally, ionic bonds occur in metals and nonmetallic elements.

While covalent bonds occur because of the use of shared electrons. In general, this bond occurs between nonmetallic elements, which has the same electron attraction

Characteristics of ionic compounds include: solid / crystalline form, soluble in water, conduct electricity

Let see the answer choices

  • Oil

It is a covalent compound because part of the hydrocarbon,  a liquid that forms a bond between elements C, H and O, and does not dissolve in water (floats on water)

  • Cornstarch

Obtained from corn which contains glucose which is a carbohydrate. It does not dissolve in water. Contains a bond between C, H and O. Includes covalent compounds

  • Sodium chloride
  • Sodium bicarbonate

Both are ionic compounds, soluble in water, in solid form

NaCl ⇒ Na⁺ + Cl⁻

NaHCO₃⇒ Na⁺ + HCO₃⁻

<h3>Learn more </h3>

ionic bonding

brainly.com/question/1603987

Type of atoms typically form covalent bonds

brainly.com/question/13648552

the ionic compound LiI

brainly.com/question/2732123#

Keywords : ionic, covalent, Oil ,Cornstarch ,Sodium chloride,Sodium bicarbonate

#LearnWithBrainly

6 0
3 years ago
Read 2 more answers
(pls help)
WITCHER [35]
Anthony’s because it explains way more
8 0
2 years ago
What mass of sodium bicarbonate do you start with
valentina_108 [34]

Answer:

84.007 g/mol

Explanation:

welcome

5 0
3 years ago
Crime scene investigators keep a wide variety of compounds on hand to help with identifying unknown substances they find in the
almond37 [142]

The powder could be acetaminophen, analgesic  having chemical formula C_{17}H_{21}NO_{4}

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule.

We are given:

Percentage of C = 67.31 %

Percentage of H = 6.978 %

Percentage of N = 4.617 %

Percentage of O = 21.10 %

Let the mass of the compound be 100 g. So, the percentages given are taken as mass.

Mass of C = 67.31 g

Mass of H = 6.978 g

Mass of N = 4.617 g

Mass of O = 21.10 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of carbon = \frac{mass}{molar \;mass}

Moles of carbon =\frac{67.31g}{12g/mole}

=5.60 moles

Moles of hydrogen = \frac{mass}{molar \;mass}

Moles of hydrogen = \frac{6.978 g}{1 g/mole}

=6.978 moles

Moles of nitrogen =\frac{mass}{molar \;mass}

Moles of nitrogen = \frac{4.617  g}{14 g/mole}

=0.329 moles

Moles of oxygen =\frac{mass}{molar \;mass}

Moles of oxygen =\frac{21.10 g}{16 g/mole}

=1.31 moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.329 moles.

We get the ratio of C : H : N : O = 17 : 21 : 1 : 4

The empirical formula for the given compound is C_{17}H_{21}NO_{4}.

Learn more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

3 0
2 years ago
How many grams are in 10.25 moles of zinc chromate?
Kobotan [32]

Answer:

1859.4 g of ZnCrO₄ in 10.25 moles

Explanation:

First of all, we determine the molecular formula of the compound:

Zinc → Zn²⁺  (cation)

Chromate → CrO₄⁻²  (anion)

Zinc chromate → ZnCrO₄

Molar mass for the compound is:

Molar mass of Zn + Molar mass of Cr + (Molar mass of O) . 4 = 181.41 g/mol

65.41 g/mol + 52 g/mol + 16 g/mol . 4 = 181.41 g/mol

Let's apply this conversion factor: 10.25 mol . 181.41 g/mol = 1859.4 g

5 0
2 years ago
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