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Thepotemich [5.8K]
3 years ago
12

How does the Law of Conservation of Mass relate to changes in physical state? How does it relate to chemical changes?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
8 0
The law of conversation of mass states that you cant create or destroy matter.By applying these to chemical changes, it implies that the left hand side of the reaction must balance with the right hand side of the reaction equation as you can neither create nor destroy atoms. this gives us a powerful tool to predict chemical reactions and the overall stoichiometrey
 of chemical reactions
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What is the density of an 84.7 g sample of an unknown substance if the sample occupies 49.6cm cubed
Ahat [919]

Answer:

             1.70 g.cm⁻³

Solution:

Data Given;

                   Mass  =  84.7 g

                   Volume  =  49.6 cm³

                   Density  =  ?

Formula Used;

                   Density  =  Mass ÷ Volume

Putting values,

                   Density  =  84.7 g ÷ 49.6 cm³ 

                   Density  =  1.70 g.cm⁻³

7 0
3 years ago
202H8(9) + 7 O2(g) > 4CO2(g) + 6 H2O(9).
lilavasa [31]

since the concentration of Carbon Dioxide will increase, it would make Q > K, cause equilibrium to shift in the direction with less moles of gas to alleviate the extra pressure. In this case, the reaction will shift left because there are fewer moles of gas present.

4 0
3 years ago
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Answer:

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6 0
3 years ago
Which chemical is the reducing agent in the redox reaction below?
posledela
Option (a) is correct.

A reducing agent is the one which loses electrons to other substance.

Here, Zn has oxidation number 0 in the L.H.S of the equation, but on R.H.S its oxidation number is +2 i.e. it Zn has donated two of its electrons to Fe^{2+}.

Hence, Zn is the reducing agent here. 
6 0
3 years ago
How many grams of ag can be formed from 5.50 grams of ag2o in the equation: 2ag2o (s) → 4ag (s) o2 (g)?
oee [108]

From the given balanced equation we have find out the amount (in gm) of Ag formed from 5.50 gm of Ag₂O.

2Ag₂O(s) → 4Ag (s) + O₂ (g)

We know, molecular mass of Ag₂O= 231.7 g/mol, and atomic mass of Ag= 107.8 g/mol. Given, mass of Ag₂O=5.50 gm. Number moles of Ag₂O=\frac{5.50}{231.7}= 0.0237 moles.

From the balanced chemical reaction we get 2 (two) moles of Ag₂O produces 4 (four) moles of Ag. So, 0.0237 moles of Ag₂O produces \frac{4X0.0237}{2} moles=0.0474 moles of Ag= 0.0474 X 107.8 g of Ag=5.11g Ag.

Therefore, 5.50 g Ag₂O produces 5.11 g of Ag as per the given balanced chemical reaction.


4 0
3 years ago
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