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Anna71 [15]
3 years ago
8

Can u pls help me with this question ​

Chemistry
2 answers:
melomori [17]3 years ago
5 0
The answer is B. condensation
NARA [144]3 years ago
3 0
B. Condensation, water which collects as droplets on a cold surface when humid air is in contact with it.
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If the ka of a monoprotic weak acid is 5.4 × 10-6, what is the ph of a 0.14 m solution of this acid?
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pH = 2.1

Let HA (aq) resembles the acid; as a weak acid (a small value of K_{a}) HA would partially dissociate to produce protons H^{+} and A^{-}, its conjugate base. Let the final proton concentration (i.e., [H^{+}]) be x. (Apparently x \ge 0) Construct the following RICE table:

\left\begin{array}{cccccc}\text{R}&HA(aq)&\rightleftharpoons&H^{+}(aq) &+ &A^{-}(aq)\\\text{I} & 0.14 \; \text{M} & &\\\text{C}&-x \; \text{M}& &+x \; \text{M} & & +x \; \text{M}\\E & (0.14 - x)\; \text{M} & & x \; \text{M} & &\+x \; \text{M}\end{array}\right

By definition, (all concentrations are under equilibrium condition)

\left\begin{array}{ccc}K_{a}&=&[H^{+}] \cdot [A^{-}] / [HA]\\&=&x^{2} /(0.14 - x)\end{array}\right

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K_a = 5.4 \cdot 10^{-6}

Equating and simplifying the two expressions gives a quadratic equation; solve the equation for x gives:

x^2 = 5.4 \cdot 10^{-6} \cdot (14 - x) \\x^2 + 5.4 \cdot 10^{-6} \cdot 14 \cdot x - 5.4 \cdot 10^{-6} \cdot 14 = 0 \\x = 0.0087 \; \text{M} \; (x \ge 0)

The pH of a solutions equals the opposite of the logarithm of its proton concentration to base 10; thus for this particular solution

\text{pH} = -\text{ln(}[H^{+}]\text{)} / \text{ln(}10\text{)} = 2.1

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Answers with detail are given below.

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Anaerobic respiration in animals pyruvate converted into lactic acid and it is not as harmful as ethanol in plant if accumulate. It is produced during exercise. It can produce the cramps which can be cured with massage.

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