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Nikolay [14]
3 years ago
5

An element that can have different physical properties or chemical arrangement is called a (n)

Chemistry
1 answer:
shusha [124]3 years ago
3 0
<h3>Answer:</h3>

D. Allotrope

<h3>Explanation:</h3>

What is allotropy?

  • Allotropy refers to the existence of an element in more than one physical forms.
  • Allotropes are therefore different forms of an element with different physical properties or chemical arrangements.

What are some examples of allotropes?

  • Examples of elements that exhibit allotropy include, sulfur and carbon.
  • Allotropes of carbon are diamond and graphite.
  • Allotropes of sulfur are monoclinic sulfur and rhombic sulfur.
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Which metal is most likely to be formed easily into
Nataly [62]

Answer:

answer is gold

Explanation:

bcz gold is having a property of malleable so it can be drawn into thin sheets

5 0
4 years ago
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How many formula units make up 24.2 g of magnesium chloride (MgCl2)?<br><br> Help!!
NNADVOKAT [17]

Answer:

Approximately 1.53 \times 10^{23} formula units (0.254\; \rm mol).

Explanation:

Refer to a modern periodic table for the relative atomic mass of magnesium (\rm Mg) and chlorine (\rm Cl):

  • \rm Mg: 24.305.
  • \rm Cl: 35.45.

In other words, the mass of 1\; \rm mol of \rm Mg atoms would be (approximately) 24.305\; \rm g.

Likewise, the mass of 1\; \rm mol of \rm Cl atoms would be approximately 35.45\; \rm g.

One formula unit of the ionic compound \rm MgCl_{2} includes exactly as many atoms as there are in the given formula. The formula mass of a compound is the mass of 1\; \rm mol of the formula units of this compound.

The formula \rm MgCl_{2} includes one \rm Mg atom and two \rm Cl atoms.

Hence, every formula unit of \rm MgCl_{2} \! would include the same number of atoms: one \rm Mg\! atom and two \rm Cl\! atoms. There would be 1\; \rm mol of \rm Mg atoms and 2\; \rm mol of \rm Cl atoms in 1\; \rm mol\! of \rm MgCl_{2} formula units.

Thus, the mass of 1\; \rm mol\! of \rm MgCl_{2} formula units would be equal to the mass of 1\; \rm mol of \rm Mg atoms plus the mass of 2\; \rm mol of \rm Cl atoms. (The mass of 1\; \rm mol\!\! of each atom could be found from the relative atomic mass of each element.)

\begin{aligned}& M({\rm MgCl_{2}}) \\ =\; & 24.305\; {\rm g \cdot mol^{-1}} + 2\times {\rm 35.45 \; \rm g \cdot mol^{-1}} \\ =\; & 95.205\; \rm g \cdot mol^{-1}\end{aligned}.

In other words, the formula mass of \rm MgCl_{2} is 95.205\; \rm g \cdot mol^{-1}.

Therefore, the number of formula units in m = 24.2\; \rm g of \rm MgCl_{2} would be:

\begin{aligned}n &= \frac{m({\rm MgCl_{2}})}{M({\rm MgCl_{2}})} \\ &= \frac{24.2\; \rm g}{95.205\; \rm g\cdot mol^{-1}} \\ & \approx 0.254\; \rm mol\end{aligned}.

Multiple n by Avogadro's Number N_{A} \approx 6.022 \times 10^{23}\; \rm mol^{-1} to estimate the number of formula units in 0.254\; \rm mol:

\begin{aligned}N &= n \cdot N_{A} \\ &\approx 0.254\; \rm mol \times 6.022 \times 10^{23}\; \rm mol^{-1} \\ &\approx 1.53\times 10^{23}\end{aligned}.

6 0
3 years ago
How is enthalpy used to predict whether a reaction is endothermic or exothermic? when the enthalpy of the reactants is higher th
mafiozo [28]
When the enthalpy change of the reaction is positive the reaction is endothermic
this means that the reaction is absorbing energy from the surrounding to the vessel
8 0
3 years ago
Read 2 more answers
Which element will gain one electron in an ionic bond?
stepladder [879]

Answer:

C. Bromine

Explanation:In ionic bond , the metals looses electron and the non metal gains electron.

In the given options ;

Aluminum (Al)= METAL

Copper (Cu) = METAL

Bromine (Br) = NON METAL

Oxygen (O) = NON METAL

That leaves us with bromine and oxygen.

Oxygen has an electronic configuration of 2,6.(see image).

So oxygen needs to gain two electrons.

Bromine has one valence electron ( see image).

So therefore , Bromine needs to gain one electron as It is in Group VII

6 0
3 years ago
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At 518°C, the rate of decomposition of a sample of gaseousacetaldehyde, initially at a pressure of 363 Torr, was 1.07 Torr s−1wh
Advocard [28]

Answer:

2nd order reaction

Explanation:

Let us assume the reaction to be:

                         R → P

Where R is the reactant and P is the product.

So here, say initially we have "a" amount of reactant.

                     <em>   R → P</em>

<em>At t=0:             a      0       (initial condition)</em>

<em>At t=t:            a-x      x </em>

Say x be the amount of reactant which forms the product in time t.

So from the rate law, we have

                 rate of decomposition = k (R)ⁿ

Where k is rate constant , R is amount of reactant at time t and n is the order of the reaction

From the question, at the instant when 5% and 20% have reacted, we will be left with 95% and 80% of the reactant respectively. So writing the rate law equation:

1.07 = k ( 95a / 100)ⁿ

0.76 = k ( 80a/100)ⁿ

Dividing these two equations, we get:

(1.07 / 0.76 ) = ( 95/80 )ⁿ

Taking logarithm on both sides we get

n = ( ㏒ (1.07 / 0.76) ) ÷ ㏒(95/80) = 2.0067 ≈ <em>2</em>

Therefore the reaction is of order 2

3 0
4 years ago
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