Answer:
The value of the partial pressure of the oxygen
= 690 torr
Explanation:
Total pressure of the mixture of gases = 736 torr
The partial pressure of water vapor = 46 torr
From the law of pressure we know that
Total pressure = The partial pressure of water vapor + The partial pressure of oxygen 
Put the values of pressures in above equation we get,
⇒ 736 = 46 + 
⇒
= 736 - 46
⇒
= 690 torr
This is the value of the partial pressure of the oxygen.
If I remember correctly, you would have to heat the reaction beaker over a burner..
I apologize if I'm wrong
Hey there!
Molar mass C2H6O = 46.0684 g/mol
Number of moles:
n = mass of solute / molar mass
n = 70.6 / 46.0684
n = 1.532 moles
Therefore:
M = number of moles / volume ( L )
M = 1.532 / 2.25
= 0.680 M
Hope that helps!
Answer:
Explanation:
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