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Neko [114]
3 years ago
11

A car is at x1 = 15m at time t1 = 5 secs & later seen at x2=20m at time t2 = 10secs. find the average velocity of the car.​

Physics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

Looks hard wish I could answer it fast

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7 0
3 years ago
Two forces are applied to a car in an effort to accel-
mestny [16]

Answer:

R=2F

Explanation:

As the forces are in same direction so the resultant force will be:

R=F+F

R=2F

4 0
3 years ago
The tension of a guitar string is increased by 40%. By what factor odes the fundamental frequency of vibration change? a. 1.13 b
bogdanovich [222]

Answer:

<h3> b. 1.18</h3>

Explanation:

The fundamental frequency in string is expressed as;

F1 = 1/2L√T/m .... 1

L is the length of the string

T is the tension

m is the mass per unit length

If the tension is increased by 40%, the new tension will be;

T2 = T + 40%T

T2 = T + 0.4T

T2 = 1.4T

The new fundamental frequency will be;

F2 = 1/2L√1.4T/m ..... 2

Divide 1 by 2;

F2/F = (1/2L√1.4T/m)/1/2L√T/m)+

F2/F = √1.4T/m ÷ √T/m

F2/F = √1.4T/√m ×√m/√T

F2/F = √1.4T/√T

F2/F = 1.18√T/√T

F2/F = 1.18

F2 = 1.18F

Hence the fundamental frequency of vibration changes by a factor of 1.18

8 0
3 years ago
A rocket blasts off vertically from rest on the launch pad with a constant upward acceleration of 2.30 m/s2. At 20.0 s after bla
lesya [120]

Answer:

Explanation:

v = u +at

u = 0

a = 2.3 m /s²

t = 20 s

v = 2.3 x 20

= 46 m /s

Distance covered under acceleration of 2.3 m/s²

s = ut + 1/2 at²

= 0 + .5 x 2.3 x 20²

= 460 m

After that it moves under free fall ie g acts on it downwards .

v² = u² - 2gh , h is height moved by it under free fall

0 = 46² - 2 x 9.8 h

h = 107.96 m

Total height attained

= 460 + 107.96

= 567.96 m

b ) At its highest point ,it stops so  its velocity = 0

c ) rocket's acceleration at its highest point = g = 9.8 downwards .

At highest  point , it is undergoing free fall so its acceleration  = g

6 0
3 years ago
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