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Lerok [7]
2 years ago
9

What happens to the work done when a force is doubled and the distance moved remain the same?​

Physics
1 answer:
san4es73 [151]2 years ago
4 0

Answer:

Work done gets doubled.

Explanation:

The work done by a force is given by :

W = Fd

Where

F is force and d is distance move

If the force is doubled and the distance moved remain the same, it would mean that the work done becomes double of the initial work done.

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If a force is 100 N and is pointing 37 degrees north of east. (a) Draw a diagram of this force. (b) Draw the force's x and y com
sasho [114]

Answer

given,

force = 100 N

Point 37 degrees north of east

a) and b) part is shown in the diagram attached below.

c) to find the x and y component of the force

x- component of the force

F_x = F cos \theta

F_x = 100\times cos 37^0

F_x = 79.86 N

y- component of the force

F_y = F sin \theta

F_y = 100\times sin 37^0

F_y = 60.18 N

3 0
3 years ago
Write the products for the following neutralization reactions
madam [21]

Answer:

answer 3

Explanation:

5 0
2 years ago
1. Why didn't Sucheng Chan go to school until she was eight
Crazy boy [7]

Answer:

Because china was in war, and her parents didn't have enough money for to go to school.

3 0
3 years ago
Earth exerts a 100 N gravitational force on a metal box. What is the magnitude of the gravitational force the metal box exerts o
jeka94

We have that the magnitude of the gravitational force  is mathematically given as

f=6.377N

<h3>Force</h3>

Question Parameters:

Earth exerts a 100 N gravitational force on a metal box.

(Mass of the earth is 6e24 kg and radius of the earth is 6.4e6m.)

Generally the equation for the Gravitational mForce  is mathematically given as

F=\frac{GMm}{r^2}\\\\Therefore\\\\F=\frac{100/9.8* 6e116e24}{6.4e6^2}

f=6.377N

For more information on Force visit

brainly.com/question/26115859

7 0
2 years ago
A 5kg object is moving at a height of 2 m. The potential energy of the object is closest to ___ j
elena55 [62]

Answer:

In this case, a body of mass 5 kg kept at a height of 10 m. So the potential energy is given as 5 * 10 *10 = 500 J.

6 0
3 years ago
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