Question

At what time after being ejected is the boulder moving at a speed 20.7 m/s upward?

Answer 1

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

What is the time after being ejected is the boulder moving at a speed 20.7 m/s upward?

The motion of the boulder is a uniformly accelerated motion, with constant acceleration

a = g = -9.8 $m / s^2$

downward (acceleration due to gravity).

By using Suvat equation:

v = u + at

where: v is the velocity at time t

u = 40.0 m/s is the initial velocity

a = g = -9.8 $m/s^2$ is the acceleration

To find the time t at which the velocity is v = 20.7 m/s

Therefore,

$t=\frac{v-u}{a}=\frac{20.7-40}{-9.8}=2.0204 \mathrm{~s}$

The time after being ejected is the boulder moving at a speed 20.7 m/s upward is 2.0204 s.

The complete question is:

A large boulder is ejected vertically upward from a volcano with an initial speed of 40.0 m/s. Ignore air resistance. At what time after being ejected is the boulder moving at 20.7 m/s upward?

To learn more about uniformly accelerated motion refer to:

brainly.com/question/14669575

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