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3 years ago

Can anyone help me with this question please I’ll mark you as a brainliest.

Mathematics

1 answer:

raketka [301]3 years ago

3 0

Answer:

Step-by-step explanation:

The other options don't correspond to the figure above.

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What is the volume of a hemisphere with a radius of 2.3 m, rounded to the nearest tenth of a cubic meter?

ANTONII [103]

Answer:25.5m^3

Step-by-step explanation:

radius(r)=2.3m

π=3.14

volume of hemisphere=2/3 x π x r^3

Volume=2/3 x 3.14x(2.3)^3

Volume=2/3 x 3.14 x 2.3 x 2.3 x 2.3

volume=(2x3.14x2.3x2.3x2.3) ➗ 3

Volume=76.40876 ➗ 3

Volume=25.5

3 0

3 years ago

At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1

sergij07 [2.7K]

Answer:

The temperature needs to decrease by 7°F to return to the original temperature.

Step-by-step explanation:

The temperature starts at 33 degrees then increases by 10 then 12 then decreases by 15 which will equal 40.

33 + 10 = 43

43 + 12 = 55

55 - 15 = 40

40 - 33 = 7

The temperature needs to decrease by 7 degrees.

5 0

3 years ago

The quality control manager of a chemical company randomly sampled twenty 100-pound bags of fertilizer to estimate the variance

lisabon 2012 [21]

Answer:

The 95% confidence interval for the variance in the pounds of impurities would be $3.829 \leq \sigma^2 \leq 14.121$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =6.62$ represent the sample variance

s=2.573 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical values.