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iris [78.8K]
2 years ago
11

The recipe calls for I cup of water to be mixed with 6 cups of cake mix. How much water should be mixed with 21 cups of cake mix

?
Mathematics
2 answers:
enot [183]2 years ago
8 0
1/x=6/21

What you need to do is set it up as a proportion.  1 cup to 6 cups cake mix, x cups to 21 cups cake mix.  

21/6 is 3.5

So 3.5 cups of water to 21 cups of cake mix (:

Hope this makes sense!
MA_775_DIABLO [31]2 years ago
7 0
The recipe calls for 1 cup of water for every 6 cups of cake mix.
So, if you take 21 and divide it by 6, which is 3.5, that's how much water you should add (in cups).
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Which digit in 49.63 has the same place value as the 7 in 8.7?
tangare [24]
6 has the same place value as the 7
8 0
3 years ago
Employees at Standard Storage are in the ratio of 2 women to 7 men. If there are 490 men employed,
PilotLPTM [1.2K]

Proportion women /men = 2/7 = x/490 7x= 2· 490 :7

X = 2·70 = 140

4 0
2 years ago
Dont really understand how to do this
bija089 [108]

Answers:

t_{10} = -22 \ \text{ and } S_{10} = -85

========================================================

Explanation:

t_1 = \text{first term} = 5\\t_2 = \text{first term}-3 = t_1 - 3 = 5-3 = 2

Note we subtract 3 off the previous term (t1) to get the next term (t2). Each new successive term is found this way

t_3 = t_2 - 3 = 2-3 = -1\\t_4 = t_3 - 3 = -1-3 = -4

and so on. This process may take a while to reach t_{10}

There's a shortcut. The nth term of any arithmetic sequence is

t_n = t_1+d(n-1)

We plug in t_1 = 5 \text{ and } d = -3 and simplify

t_n = t_1+d(n-1)\\t_n = 5+(-3)(n-1)\\t_n = 5-3n+3\\t_n = -3n+8

Then we can plug in various positive whole numbers for n to find the corresponding t_n value. For example, plug in n = 2

t_n = -3n+8\\t_2 = -3*2+8\\t_2 = -6+8\\t_2 = 2

which matches with the second term we found earlier. And,

tn = -3n+8\\t_{10} = -3*10+8\\t_{10} = -30+8\\t_{10} = \boldsymbol{-22} \ \textbf{ is the tenth term}

---------------------

The notation S_{10} refers to the sum of the first ten terms t_1, t_2, \ldots, t_9, t_{10}

We could use either the long way or the shortcut above to find all t_1 through t_{10}. Then add those values up. Or we can take this shortcut below.

Sn = \text{sum of the first n terms of an arithmetic sequence}\\S_n = (n/2)*(t_1+t_n)\\S_{10} = (10/2)*(t_1+t_{10})\\S_{10} = (10/2)*(5-22)\\S_{10} = 5*(-17)\\\boldsymbol{S_{10} = -85}

The sum of the first ten terms is -85

-----------------------

As a check for S_{10}, here are the first ten terms:

  • t1 = 5
  • t2 = 2
  • t3 = -1
  • t4 = -4
  • t5 = -7
  • t6 = -10
  • t7 = -13
  • t8 = -16
  • t9 = -19
  • t10 = -22

Then adding said terms gets us...

5 + 2 + (-1) + (-4) + (-7) + (-10) + (-13) + (-16) + (-19) + (-22) = -85

This confirms that S_{10} = -85 is correct.

6 0
2 years ago
Find the 10th term of an arithmetic sequence if the common difference is 32 and the first term is 2
zaharov [31]

Answer:

290

Step-by-step explanation:

If the first term is 2 and the common difference is 32, then the formula for a(n) is:

a(n) = 2 + 32(n-1).

Thus, the 10th term is a(10) = 2 + 32(10-1)  =  2 + 32(9) = 290

6 0
3 years ago
Use the unit circle to find tan 60°
8_murik_8 [283]

Answer:3

Step-by-step explanation:

5 0
3 years ago
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