Since b^2 - 4ac = 9-16 < 0
There is no real root present.
Convert both 1/5 and 1/4 to 20ths to get 4/20 and 5/20. From there just add the two together getting 9/20 of the trip done and 11/20 to go. Hope this answers your questions.
Solve for
y
y in
5
x
−
y
=
8
5x−y=8.
y
=
5
x
−
8
y=5x−8
2 Substitute
y
=
5
x
−
8
y=5x−8 into
2
0
x
−
4
y
=
2
4
20x−4y=24.
3
2
=
2
4
32=24
3 Since
3
2
=
2
4
32=24 is not true, this is an inconsistent system.
Y+4<u><</u>9
subtract 4
y<u><</u>5
y is smaller than and equal to 5
so you shade from 5 to the negative end to infinity (to the left) and shade the 5 to show that it is included (attachment says A)
6 less than (-6) 2 times a number (2 time x) is greater than (>) 8 (8)
-6+2x>8
add 6
2x>14
divide 2
x>7
so
x is bigger than 7
shade from 7 to the positive end to infinity (to the right) and don't shade 7 but put a circle around it to show that it is not included (attachment says B )
I have included pictures of the number lines
Put -4 in place of x
-4 to the second power is 16 so it would be 16-(-12)= 28