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Murrr4er [49]
2 years ago
8

For the total population of a large southern city, mean family income is

Mathematics
1 answer:
Vlad [161]2 years ago
3 0

Answer:

Z= -2.83

Brainliest please if you dont mind

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Do this pls 35 points
love history [14]

Answer:

x = 68

Step-by-step explanation:

If you look at the triangle properly, it is a isosceles triangle where two legs are equal to each other.

The answer for x will be:

56 + 56 + x =180

112 + x = 180

x = 68

7 0
3 years ago
What is the solution to the system of equations below?
Alekssandra [29.7K]
(6,2) because X would equals 6 multiplied by 2 equals 12. Now minus 2 and that gives you a equilibrium of 10
3 0
3 years ago
What is the surface area of the figure?
Oliga [24]

Answer:

The total surface area = 582 ft²

Step-by-step explanation:

To find the surface area of it count the number of faces at first

The figure has 8 faces each 2 are equal

1- Two faces with dimensions 4 ft and 15 ft ( base and shaded face)

2- Two faces with dimensions 9 ft and 4 ft

3- Two faces with dimensions 4 ft and 6 ft

4- Two faces with dimensions 15 ft , 9 ft and 6 ft

Area of (1-) = 2(4 × 15) = 120 ft²

Area of (2-) = 2(4 × 9) = 72 ft²

Area of (3-) = 2(4 × 6) = 48 ft²

Area of (4-) = 2[(9 × 9) + (6 × 15)] = 2[81 + 90] = 2 × 171 = 342 ft²

∴ The total surface area = 120 + 72 + 48 + 342 = 582 ft²

5 0
3 years ago
4x + 2y = 8 16x - y = 14
lys-0071 [83]
Equation 1)  4x + 2y = 8
Equation 2)  16x - y = 14

Multiply all of equation 2 by 2.

2)  2(16x - y = 14)

2)  32x - 2y = 28
1)  4x + 2y = 8

Add equations together.

36x = 36

Divide both sides by 36.

x = 1

Plug in 1 for x in the first equation.

4x + 2y = 8

4(1) + 2y = 8

4 + 2y = 8

Subtract 4 from both sides.

2y = 8 - 4

2y = 4

Divide both sides by 2.

y = 4/2

y = 2

So, x = 1, y = 2

~Hope I helped!~
7 0
3 years ago
Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x​
Tanzania [10]

Recall that

\cosh^2(x) - \sinh^2(x) = 1

Dividing both sides by cosh²(x) gives

1 - \tanh^2(x) = \mathrm{sech}^2(x)

Also, recall the identity

\sinh(2x) = 2\sinh(x)\cosh(x)

Then

\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)

4 0
3 years ago
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