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motikmotik
3 years ago
7

1. inspiration meaning​

Chemistry
2 answers:
Furkat [3]3 years ago
6 0

Answer:

inspiration means

the process of being mentally stimulated to do or feel something, especially to do something creative.

vitfil [10]3 years ago
3 0

Answer:

The process of being mentally stimulated to do or feel something, especially to do something creative.

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Na2o + h2so4 ———&gt; na2so4 + h2o<br><br><br> Can anyone balance this please!!??
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The equation is already balanced. There's an equal number of materials on each side of the equation.

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(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
Shkiper50 [21]

Answer:

The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

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3 years ago
A vessel of 120ml capacity contains a certain amount of gas at 35°C and 1.2 bar pressure. The gas is transferred to another vess
Rainbow [258]

Given parameters:

Initial volume  = 120ml

Initial temperature  = 35°C

Initial pressure  = 1.2bar

Final volume  = 180ml

Final temperature  = 35°C

Unknown:

Final pressure  = ?

To solve this problem, we apply the combined gas law. The expression is given below;

          \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

Where P₁ is the initial pressure

           P₂ is the final pressure

          V₁ is the initial volume

          V₂ is the final volume

          T₁ is the initial temperature

           T₂ is the final temperature

We need to convert the parameters to standard units

take the volume to dm³;

      1000ml  = 1dm³

      120ml  = \frac{120}{1000} dm³  = 0.12dm³ = initial volume

Final volume;

      1000ml = 1dm³

      180ml  = \frac{180}{1000} dm³  = 0.18dm³

Now, the temperature;

       K  = 273 + °C

Initial temperature  = 273 + 35  = 308k

Final temperature  = 308k

We then input the parameters into the equation;

         \frac{1.2bar x 0.12 }{308}   = \frac{P_{2} x 0.18 }{308}

       Solving for P₂;

     P₂  = 0.8bar

The new pressure or final pressure in the vessel is 0.8bar

5 0
3 years ago
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