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Aloiza [94]
3 years ago
9

Please help!! Need to know what it is!

Chemistry
2 answers:
Kamila [148]3 years ago
7 0

Answer:

The correct answer will be 15

Sidana [21]3 years ago
5 0

Answer:

<h3>15 </h3>

Explanation:

  • it is fifteen. 15 heheheehehehhehehehehehhehehe
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2C3H6O + 8O2 --&gt; 6CO2 + 6H2O
grigory [225]

Answer: 0.45 moles of H_2O will be produced from 0.15 moles of propanol.

Explanation:

The balanced chemical reaction is:

2C_3H_6O+8O_2\rightarrow 6CO_2+6H_2O

C_3H_6O is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

According to stoichiometry :

2 moles of C_3H_6Oproduces = 6 moles of H_2O

Thus 0.15 moles of V will produce=\frac{6}{2}\times 0.15=0.45moles  of H_2O

Thus 0.45 moles of H_2O will be produced from 0.15 moles of propanol.

7 0
3 years ago
Direction: To compare and differentiate the animal and plant cell base on the presence and absence of certain organelles.Fill in
S_A_V [24]

Answer:

hi what are you doing

Explanation:

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3 0
2 years ago
A 1.30M solution of BaCl2 has a density of 1.230 g/ml. a) What is the mole fraction of BaCl2 in this solution?
Elodia [21]

<u>Answer:</u> The mole fraction of barium chloride in the solution is 0.024

<u>Explanation:</u>

We are given:

Molarity of barium chloride solution = 1.30 M

This means that 1.30 moles of barium chloride is present in 1 L or 1000 mL of solution.

  • To calculate the mass of solution, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Density of solution = 1.230 g/mL

Volume of solution = 1000 mL

Putting values in above equation, we get:

1.230g/mL=\frac{\text{Mass of solution}}{1000mL}\\\\\text{Mass of solution}=(1.230g/mL\times 1000mL)=1230g

  • To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}     .....(1)

Moles of barium chloride = 1.30 moles

Molar mass of barium chloride = 208 g/mol

Putting values in equation 1, we get:

1.30mol=\frac{\text{Mass of barium chloride}}{208g/mol}\\\\\text{Mass of barium chloride}=(1.30mol\times 208g/mol)=270.4g

Mass of water = Mass of solution - Mass of barium chloride

Mass of water = 1230 - 270.4 = 959.6 g

<u>Calculating the moles of water:</u>

Given mass of water = 959.6 g

Molar mass of water = 18 g/mol

Putting values in equation 1, we get:

\text{Moles of water}=\frac{959.6g}{18g/mol}\\\\\text{Moles of water}=53.31mol

Mole fraction of a substance is given by:

\chi_A=\frac{n_A}{n_A+n_B}

  • <u>For barium chloride:</u>

\chi_{\text{(barium chloride)}}=\frac{n_{\text{(barium chloride)}}}{n_{\text{(water)}}+n_{\text{(barium chloride)}}}

\chi_{\text{(barium chloride)}}=\frac{1.30}{1.30+53.31}\\\\\chi_{\text{(barium chloride)}}=0.024

Hence, the mole fraction of barium chloride in the solution is 0.024

6 0
4 years ago
The sun produces energy by forming ____ in its core.
taurus [48]
The sun produces energy by forming helium Its core
5 0
4 years ago
What volume will 0.75 moles of oxygen gas occupy at STP?
OleMash [197]
I believe the answer would be 16.8
8 0
3 years ago
Read 2 more answers
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