Question

What volume will 0.75 moles of oxygen gas occupy at STP?

Answer 1

I believe the answer would be 16.8

Answer 2

Answer: Volume occupied by oxygen gas at STP is 16.78 liters.

Explanation:

At STP, value of pressure ,P = 1atm

At STP, value of Temperature ,T =  273 K

Number moles of oxygen gas ,n= 0.75 moles

According to ideal gas equation :

PV=nRT, R = Universal Gas constant = 0.0820 L atm/mol K

$1 atm\times V=0.75 mol\times 0.0820 L atm/mol K\times 273 K$

$V=\frac{0.75 mol\times 0.0820 L atm/mol K\times 273 K}{1 atm}=16.78 L$

Volume occupied by oxygen gas at STP is 16.78 liters.