Answer should be <span>t=<span>−<span><span>1<span> or </span></span>t</span></span></span>=<span>5</span>
Answer:
Explanation:
Let the first height be h . second height .75h
third height .75h . fourth height .75²h
fifth height .75²h , sixthth height .75³ and so on
Total distance consists of two geometric series as follows
1 ) first series
h + .75h + .75²h + .75³h......
2 ) second series
.75h +.75²h +.75³h + .75⁴h .......
Sum of first series :
first term a = h , commom ratio r = .75
sum = a / (1 - r )
= h / 1 - .75
= h / .25
4h
sum of second series :--
first term a = .75 h , commom ratio r = .75
sum = a / (1 - r )
= .75h / 1 - .75
= .75h / .25
3h
Total of both the series
= 4h + 3h
= 7h .
h = 1 m
Total distance = 7 m
Answer:
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Stability and Balance
Explanation:
UP
Answer: Wallahi i don't know
Explanation:because i don't really care
Answer:
It would be a straight line
Explanation:
On a distance-time graph, an object that moves at constant speed would be represented by a straight line.
In fact, in a distance-time graph, the slope of the line corresponds to the speed of the object. We can demonstrate that. In fact:
- The speed of the object is equal to the ratio between the distance covered
and the time taken (
):

On a distance-time graph, the distance is on the y-axis while the time is on the x-axis. The slope of the line is defined as:

But the variation on the y-axis (
) is equal to the distance covered (
), while the variation on the x-axis
corresponds to the time taken (
), so the slope can also be rewritten as

which is equal to the speed of the object. Therefore, an object moving at constant speed would be represented by a line with constant slope, which means a straight line.