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Svetllana [295]
3 years ago
12

How can a cyclist minimize friction as he or she rides? A. by increasing the weight of the bike B. by increasing the tread on hi

s or her tires C. by decreasing the air resistance D. by decreasing aerodynamic design
Physics
2 answers:
erastova [34]3 years ago
7 0
The answer is B becausew the others would add friction
jek_recluse [69]3 years ago
6 0
B I believe is the answer!

Hope this helps and have a great day!!!
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PLZ Help ASAP
Tasya [4]

Answer:

C. Fill two identical pots with equal volumes of salt water and tap water and use a stopwatch to determine the time it takes each pot to boil.

Explanation:

<u>A) is incorrect</u> because Peter should have the same testing environment for both of his experiments.

He should choose the same method of boiling the salt water and tap water because the stovetop and the microwave could also affect the results and make them unreliable.

<u>B) is incorrect</u> because Peter should not estimate the time it takes the salt water and tap water to boil.

Peter should measure and record the amount of time that it takes these substances to boil in order to have an accurate, valid experimental thesis.

<u>C) is correct</u> because Peter uses the same volume of salt water and tap water, fills them into two identical pots, and uses a stopwatch to determine the amount of time it takes each pot to boil.

The stopwatch makes the experiment more valid and accurate compared to the previous methods, and the identical pots and amounts of water help this experiment become even more precise.

<u>D) is incorrect</u> because the variables in the experiment are not controlled amounts and will therefore produce an inaccurate and invalid experiment.

6 0
3 years ago
Read 2 more answers
A 1000-turn solenoid is 50 cm long and has a radius of 2.0 cm. It carries a current of 18.0 A. What is the magnetic field inside
vitfil [10]

Answer:

The value  is  B =  0.0452 \  T

Explanation:

From the question we are told that

   The number of turns is  N  =  1000

    The length is  L =  50 cm =  0.50 m  

    The radius is  r =  2.0 cm  =  0.02 m

     The current is I  =  18.0 A

   

Generally the magnetic field is mathematically represented as

         B = \mu_o  * \frac{N }{L}  *  I

Here \mu_o is the permeability of free space with value  

     \mu_o  =  4\pi * 10^{-7} N/A^2

So

     B =  4\pi * 10^{-7}  *   \frac{1000}{0.50} *  18.0

=>   B =  0.0452 \  T

3 0
3 years ago
Orbital Motion<br> Project: Career Multimedia Presentation
Yuliya22 [10]

Answer:

can you post the full question plz

Explanation:

4 0
2 years ago
An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?
ikadub [295]
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
7 0
3 years ago
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d
padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

#SPJ10

3 0
2 years ago
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