Answer:
5.85 m/s²
Explanation:
Mass of pulley (M) = 6.8 kg, mass of bucket (m) = 1.5 kg, radius of pulley (r) = 0.816 m, acceleration due to gravity (g) = 10 m/s².
Let the tension exerted on the pulley be T and the angular acceleration be α,
The angular acceleration (α) = a / r; where a is the linear acceleration.
mg - T = ma
T = m(g - a)
Also, for the disk:
Tr = Iα
I = moment of inertia = 0.5Mr²
m(g - a)r = 0.5Mr²(a/r)
m(g - a)r = 0.5Mra
2m(g - a) = Ma
2mg - 2ma = Ma
Ma + 2ma = 2mg
a(M + 2m) = 2mg
a = 2mg / (M + 2m)
Substituting:
a = 2(3.1 kg)(10 m/s²) / (4.4 + 2(3.1))
a = 5.85 m/s²
Yeah what do you want me to answer for this question?
Answer:
the diameter of the smaller vessels is 9.90 mm
Explanation:
The computation of the diameter of the smaller vessels is given below;
Given that
The larger vessel of the diameter is 14mm
So,
d1 = 7 mm
let us assume the diameter of the smaller artery is d2
Now we used the equation of continuity i.e.
v × pi × d1^2 = 2 × v × pi × d2^2
14^2 = 2 × d2^2
d2 = 9.90 mm
Hence, the diameter of the smaller vessels is 9.90 mm
