Answer:
the answer is 30 Ohms. Not found in the options provided
Lol i think i had the same worksheet!! lol anyway look up newtons first law and it will be pretty self explanatory from there
Answer:
The value of impulse of the net force on the ball during its collision with wall is 
The value of average horizontal force that the wall exerts on the ball during the impact is F = 15000 N
Explanation:
Mass of the ball = 0.5 kg
Horizontal velocity
= 20 
Velocity after collision
= - 10 
(A). Impulse of the net force on the ball during its collision with wall is

I = 0.5 × (20 + 10)

This is the value of impulse of the net force on the ball during its collision with wall.
(B). The magnitude of average horizontal force

Where F = Force
I = impulse & t = time interval = 0.001 sec

F = 15000 N
This is the value of average horizontal force that the wall exerts on the ball during the impact.
Answer:
41°
Explanation:
refractive index of glass, n = 1.52
For total internal reflection, the angle of refraction in rarer medium is 90°.
r = 90°
Let the angle of refraction in denser medium, that means in glass is i.
By use of Snell's law
refractive index of rarer medium with respect to denser medium, that means refractive index of air with respect to glass = 1 / n
And



i = 41°
Thus, the angle of incidence should be 41°.
Answer:
d. 12.30 grams
Explanation:
Given the following data;
Force = 652 N
Acceleration = 53 m/s²
To find how much the object weigh, we would need to determine its mass;
Force = mass * acceleration
652 = mass * 53
Mass = 652/53
<em>Mass = 12.30 grams.</em>
<em>Therefore, the object weighs 12.30 grams. </em>