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Marta_Voda [28]
3 years ago
6

What happens to the force of gravity between two masses if one mass is decreased?

Physics
2 answers:
Andrews [41]3 years ago
7 0
<span>B. It stays the same</span>
Cloud [144]3 years ago
4 0

B. It stays the same

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What is the net force when forces applied are 300 N to the right and 100 N to the right
labwork [276]

Answer:

400 Newtons to the right.

Explanation:

You have 300 Newtons that are being applied to the right and you also 100 Newtons to the right. When calculating net force with the forces that go the same direction, you add them. 300 plus 100 is 400. Therefore, it is 400 Newtons or N to the right. Hope this helps!

8 0
3 years ago
3. What is the mass of a paratrooper who experiences an air resistance of 400 N and an acceleration of 4.5 m/s2
goblinko [34]

Answer:

88.89kg

Explanation:

The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.

4 0
3 years ago
URGENTE. ¿Qué fuerzas actúan en un tobogán?
professor190 [17]

Answer:

friction or fricción

if u only speak spanish

Explanation:

5 0
3 years ago
Given the thermochemical equations X2+3Y2⟶2XY3ΔH1=−370 kJ X2+2Z2⟶2XZ2ΔH2=−120 kJ 2Y2+Z2⟶2Y2ZΔH3=−270 kJ Calculate the change in
Alchen [17]

Answer : The change in enthalpy of the reaction is, -310 kJ

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

4XY_3+7Z_2\rightarrow 6Y_2Z+4XZ_2    \Delta H=?

The intermediate balanced chemical reaction will be,

(1) X_2+3Y_2\rightarrow 2XY_3     \Delta H_1=-370kJ

(2) X_2+2Z_2\rightarrow 2XZ_2    \Delta H_2=-120kJ

(3) 2Y_2+Z_2\rightarrow 2Y_2Z    \Delta H_3=-270kJ

Now we will reverse the reaction 1 and multiply reaction 1 by 2, reaction 2 by 2 and reaction 3 by 3 then adding all the equations, we get :

(1) 4XY_3\rightarrow 2X_2+6Y_2     \Delta H_1=2\times (+370kJ)=740kJ

(2) 2X_2+4Z_2\rightarrow 4XZ_2    \Delta H_2=2\times (-120kJ)=-240kJ

(3) 6Y_2+3Z_2\rightarrow 6Y_2Z    \Delta H_3=3\times (-270kJ)=-810kJ

The expression for enthalpy of formation of CH_4 will be,

\Delta H=\Delta H_1+\Delta H_2+\Delta H_3

\Delta H=(+740kJ)+(-240kJ)+(-810kJ)

\Delta H=-310kJ

Therefore, the change in enthalpy of the reaction is, -310 kJ

5 0
3 years ago
Will a seismic wave traveling through a solid go slower or faster than a seismic wave traveling through a liquid? Why?
Snezhnost [94]
You can't answer this question because you aren't giving the specific type of seismic waves. There is an s-wave a p-wave and an l-wave. Those are the basic waves. An S-wave cannot travel through a liquid at all. So, obviously it travels slower than any other seismic wave. 


<span>It would travel faster because their speed depends on the density and composition of material that they pass through.</span>
3 0
3 years ago
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