You would expect 500 million atoms to be present. When a source experiences a half-life, it is a point in which atoms have degraded to half what they used to be in mass. 1/2(1 billion) = 500 million
Brainliest answer please
The answer is <span>ReGallium or Indium</span>
Solution :
In the process to isolate gold that has a 80 percent yield, a 3.00 g of Au is being isolated.
That is, the actual yield of Au is 3. 00 g
Therefore, we need to find the theoretical yield.
As we know,
As actual yield = 3.00 g
percent yield = 80 %
So, theoretical yield = 
= 3.75 g
Thus he should be able to get 3.75 g which is the theoretical yield of Au.
A sample of material is found to have a mass if 33.03 grams (g), and a volume of 2.624 ml, hence the metal is Silver.
∴ Silver = 12.59 g/mL
The elements of group 11 (Cu, Ag, and Au) are called coinage metals because they are used in minting coins. These metals are malleable. They have the ability to get converted into sheets.
The coinage metal comprise, at a minimum, those metallic chemical elements which have historically been used as components in alloys used to mint coins.
The coinage metals have the highest electrical and thermal conductivities of all the metals, and they are also the most ductile and malleable.
To learn more about coinage metals here
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The ph of a saturated solution of Ca(OH)2 is 12.35
CALCULATION:
For the reaction
Ca(OH)2 → Ca2+ + 2OH-
we will use the Ksp expression to solve for the concentration [OH-] and then use the acid base concepts to get the pH:
Ksp = [Ca2+][OH-]^2
The listed Ksp value is 5.5 x 10^-6. Substituting this to the Ksp expression, we have
Ksp = 5.5 x 10^-6 = (s) (2s)^2 = 4s^3
s3 = 5.5x10^-6 / 4
Taking the cube root, we now have
s = cube root of (5.5x10^-6 / 4)s
= 0.01112
We know that the value of [OH-] is actually equal to 2s:
[OH-] = 2s = 2 * 0.01112 = 0.02224 M
We can now calculate for pOH:
pOH = - log [OH-]
= -log(0.02224)
= 1.65
Therefore, the pH is
pH = 14 - pOH
= 14 - 1.65
= 12.35
