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Setler [38]
3 years ago
14

Gold has a density of 19.32 g>cm3. A piece of gold foil is 2.50 cm on each side and 0.100 mm thick. How many atoms of gold ar

e in this piece of gold foil
Chemistry
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

The answer to your question is 3.69 x 10²¹ atoms of gold

Explanation:

Data

density = 19.32 g/cm³

dimensions = 2.5 cm x 2.5 cm x 0.1 mm

number of atoms of gold = x

Process

1.- Find the volume of the foil

Volume = length x height x width

Volume = 2.5 x 2.5 x 0.01

Volume = 0.0625 cm³

2.- Calculate the mass of the foil

Density = mass/volume

mass = density x volume

mass = 19.32 x 0.0625

mass = 1.208 g

3.- Calculate the number of atoms

Atomic number of Gold = 197 g

                    197 g -------------------- 6.023 x 10²³ atoms

                      1.208 g ---------------  x

                       x = (1.208 x 6.023 x 10²³)/197

                       x = 3.69 x 10²¹ atoms of gold

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Answer:

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Explanation:

To identify the gas, you first need to find the moles of the gas. You can do this using the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

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-----> T = temperature (K)

After converting mL to L and Celsius to Kelvin, you can plug the values into the equation and simplify to find the moles.

P = 1.98 atm                                            R = 0.08206 atm*L/mol *K

V = 752 mL / 1,000 = 0.752 L                T = 62 °C + 273.15 = 335.15 K

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(1.98 atm)(0.752 L) = n(0.08206 atm*L/mol *K)(335.15 K)

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You can identify the gas by determining the molar mass of the gas, which is specific to each element. The molar mass exists as a ratio that compares the mass per 1 mole.

Molar Mass = mass / moles

Molar Mass = 4.32 g / 0.0541 moles

Molar Mass = 79.8 g/mol

This molar mass is closest to the molar mass of bromine (79.904 g/mol).

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