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Setler [38]
3 years ago
14

Gold has a density of 19.32 g>cm3. A piece of gold foil is 2.50 cm on each side and 0.100 mm thick. How many atoms of gold ar

e in this piece of gold foil
Chemistry
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

The answer to your question is 3.69 x 10²¹ atoms of gold

Explanation:

Data

density = 19.32 g/cm³

dimensions = 2.5 cm x 2.5 cm x 0.1 mm

number of atoms of gold = x

Process

1.- Find the volume of the foil

Volume = length x height x width

Volume = 2.5 x 2.5 x 0.01

Volume = 0.0625 cm³

2.- Calculate the mass of the foil

Density = mass/volume

mass = density x volume

mass = 19.32 x 0.0625

mass = 1.208 g

3.- Calculate the number of atoms

Atomic number of Gold = 197 g

                    197 g -------------------- 6.023 x 10²³ atoms

                      1.208 g ---------------  x

                       x = (1.208 x 6.023 x 10²³)/197

                       x = 3.69 x 10²¹ atoms of gold

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5 0
3 years ago
What types of emergency situations could rescue workers be in that would make it difficult for them to get energy to their elect
artcher [175]

Answer:

Large-scale natural disasters

Explanation:

The emergency situation that rescue workers could be in that would make it difficult for them to get energy to their electrical devices is "Large-scale natural disasters"

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4 0
4 years ago
1.) A metal...
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Answer:

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5 0
3 years ago
A laboratory analysis of a sample finds it is composed of 38.8% carbon, 16.2% hydrogen, and 45.1% nitrogen. What is its empirica
Sladkaya [172]

Answer: The empirical formula for the given compound is CH_5N

Explanation : Given,

Percentage of C = 38.8 %

Percentage of H = 16.2 %

Percentage of N = 45.1 %

Let the mass of compound be 100 g. So, percentages given are taken as mass.

Mass of C = 38.8 g

Mass of H = 16.2 g

Mass of N = 45.4 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{38.8g}{12g/mole}=3.23moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{16.2g}{1g/mole}=16.2moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{45.4g}{14g/mole}=3.24moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.23 moles.

For Carbon = \frac{3.23}{3.23}=1

For Hydrogen  = \frac{16.2}{3.23}=5.01\approx 5

For Oxygen  = \frac{3.24}{3.23}=1.00\approx 1

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : N = 1 : 5 : 1

Hence, the empirical formula for the given compound is C_1H_5N_1=CH_5N

3 0
3 years ago
deduce the chemical formula of strontium chloride, if 264g of strontium react with 213g of chloride?​
zheka24 [161]
Strontium and chlorine react to form strontium chloride with the formula SrCl2.
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3 years ago
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