Question

Gold has a density of 19.32 g>cm3. A piece of gold foil is 2.50 cm on each side and 0.100 mm thick. How many atoms of gold are in this piece of gold foil

Answer 1

Answer:

The answer to your question is 3.69 x 10²¹ atoms of gold

Explanation:

Data

density = 19.32 g/cm³

dimensions = 2.5 cm x 2.5 cm x 0.1 mm

number of atoms of gold = x

Process

1.- Find the volume of the foil

Volume = length x height x width

Volume = 2.5 x 2.5 x 0.01

Volume = 0.0625 cm³

2.- Calculate the mass of the foil

Density = mass/volume

mass = density x volume

mass = 19.32 x 0.0625

mass = 1.208 g

3.- Calculate the number of atoms

Atomic number of Gold = 197 g

                    197 g -------------------- 6.023 x 10²³ atoms

                      1.208 g ---------------  x

                       x = (1.208 x 6.023 x 10²³)/197

                       x = 3.69 x 10²¹ atoms of gold