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Setler [38]
3 years ago
14

Gold has a density of 19.32 g>cm3. A piece of gold foil is 2.50 cm on each side and 0.100 mm thick. How many atoms of gold ar

e in this piece of gold foil
Chemistry
1 answer:
Agata [3.3K]3 years ago
5 0

Answer:

The answer to your question is 3.69 x 10²¹ atoms of gold

Explanation:

Data

density = 19.32 g/cm³

dimensions = 2.5 cm x 2.5 cm x 0.1 mm

number of atoms of gold = x

Process

1.- Find the volume of the foil

Volume = length x height x width

Volume = 2.5 x 2.5 x 0.01

Volume = 0.0625 cm³

2.- Calculate the mass of the foil

Density = mass/volume

mass = density x volume

mass = 19.32 x 0.0625

mass = 1.208 g

3.- Calculate the number of atoms

Atomic number of Gold = 197 g

                    197 g -------------------- 6.023 x 10²³ atoms

                      1.208 g ---------------  x

                       x = (1.208 x 6.023 x 10²³)/197

                       x = 3.69 x 10²¹ atoms of gold

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Malonic acid, h2c3h2o4, is a diprotic acid with ka1= 1.5 x 10-3and ka2= 2.0 x 10-6. what is the concentration of the malonate an
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In a 0.15 m solution of malonic acid, the amount of the malonate anion, c3h2o42-, is 1.68*10^{-4} M.

Explanation:

For the first equlibria;

initial concentration of H_{2}C_{3}H_{2}OH=0.15

initial concentration of HC_{3}H_{2}O_{4}^{-} =0

initial concentration of H^{+} =0

Let concentration change of H_{2}C_{3}H_{2}OH=-x

Let concentration change of HC_{3}H_{2}O_{4}^{-} =+x

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x=0.01427

Therefore, HC_{3}H_{2}O_{4}^{-} =x= 0.01427M

Now for the second equlibria;

initial concentration of HC_{3}H_{2}O_{4}^{-}=0.01427

initial concentration of C_{3}H_{2}O_{4}^{2-} =0

initial concentration of H^{+} =0

Let concentration change of HC_{3}H_{2}O_{4}^{-}=-x

Let concentration change of  C_{3}H_{2}O_{4}^{2-} =+x

Let concentration change of H^{+} =+x

Let concentration in equilibrium state of  HC_{3}H_{2}O_{4}^{-}=0.01427-x

Let concentration in equilibrium state ofC_{3}H_{2}O_{4}^{2-} =x

Let concentration in equilibrium state ofH^{+} =x

Therefore, Ka_{2}=\frac{x*x}{0.01427-x}=\frac{2.0*10^{-6}}{1} =\frac{x^{2}}{0.01427-x}

2.854*10^{-8}-(2.0*10^{-6})x=x^{2}

Therefore, C_{3}H_{2}O_{4}^{2-} =x= 1.68*10^{-4}M

<h3>What is a malonic acid?</h3>

The chemical formula of malonic acid is CH2(COOH)2. Malonates include the ionized form of malonic acid as well as its esters and salts. For instance, the diethyl ester of malonic acid is called diethyl malonate.

Polyester and polymers both employ malonic acid as a precursor. Both the scent business and the flavoring sector utilize it. It is employed to regulate acidity. Malonic acid contributes to the production of fatty acids in people. Malonic acid has been found in a number of foods outside of the human body, including red beets, corn, scarlet beans, common beets, and cow milks, although its presence has not been defined. The group of organic substances known as dicarboxylic acids and derivatives includes malonic acid, also known as malonate or H2MALO.

To know more about malonic acid, visit:

brainly.com/question/13943912?referrer=searchResults

#SPJ4

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