The total number of matchbooks required would 5,000 be and the cost would be $144
<h3>Mathematical ratios</h3>
50 matchbooks = $1.44
Each matchbook = 0.005 grams red phosphorus
25 grams of red phosphorus is needed:
25/0.005 = 5,000 matchbooks
5,000 matchbooks will cost:
5000/50 x 1.44 = $144
More on mathematical ratios can be found here: brainly.com/question/20387079
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I will solve this question assuming the reaction equation look like this:
<span>MnO2 + 4 HCl ---> MnCl2 + Cl2 + 2 H2O.
</span>
For every one molecule of MnO2 used, there will be one molecule of Cl2 formed. If the molecular mass of MnO2 is 87g/mol and molecular mass of Cl2 is <span> 73.0 g/mol, the mass of MnO2 needed would be:
Cl mass/Cl molecular mass * MnO2 molecular mass=
25g/ (73g/mol) * (87g/mol) * 1/1= 29.8 grams</span>
Answer:
Percent yield = 94.5%
Theoretical yield = 26.89 g
Explanation:
Given data:
Mass of copper = 12.5 g
Mass of copper chloride produced = 25.4 g
Theoretical yield = ?
Percent yield = ?
Solution:
Cu + Cl₂ → CuCl₂
Number of moles of Copper:
Number of moles = mass/ molar mass
Number of moles = 12.5 g/ 63.55 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of copper with copper chloride.
Cu : CuCl₂
1 : 1
0.2 : 0.2
Theoretical yield:
Mass of copper chloride:
Mass = Number of moles × molar mass
Mass = 0.2 mol × 134.45 g/mol
Mass = 26.89 g
Percent yield:
Percent yield = Actual yield / theoretical yield × 100
Percent yield = 25.4 g/26.89 g × 100
Percent yield = 94.5%
<span><span>Atomic number36,</span><span>Atomic mass<span>83.80 g.mol -1,</span></span><span>Density<span>3.73 10-3 g.cm-3 at 20°C,</span></span><span>Melting point- 157 °C,</span><span>Boiling point<span>- 153° C</span></span></span>
•CaCO3
Includes;Calcium,Carbon and Oxygen
•CaCl2 consists of; Calcium and Chlorine
•CHO consists of; Carbon,Hydrogen and Oxygen
•HCl consists of; Hydrogen and Chlorine
•Ca(OH)2 consists of; Calcium,Oxygen and Hydrogen
Hope I helped
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