I believe that its easier to understand the multiplication of a radical than that of a polynomial.
<h3>How to illustrate the information?</h3>
In mathematics, a radical is the opposite of an exponent that is represented with a symbol '√' also known as root.
A polynomial is an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division.
When multiplying radicals with the same index, multiply under the radical, and then multiply in front of the radical. An example is:
= 3✓2 × 4✓2
= 12✓4
= 12 × 2
= 24
The multiplication of a radical is easier.
Learn more about polynomial on:
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Answer:
C. The 6th term is positive/negative 80
Step-by-step explanation:
Given
Geometric Progression


Required

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;
To solve the common ratio;
Divide the 7th term by the 5th term; This gives

Divide the numerator and the denominator of the fraction by 40
----- equation 1
Recall that the formula of a GP is

Where n is the nth term
So,


Substitute the above expression in equation 1
becomes


Square root both sides

r = ±
Next, is to solve for the first term;
Using 
By substituting 160 for T5 and ±
for r;
We get


Multiply through by 16



Now, we can easily solve for the 6th term
Recall that the formula of a GP is

Here, n = 6;



r = ±
So,
or 
or 
or 
±80
Hence, the 6th term is positive/negative 80
Answer:
angle B: 39
AC: 7.288
AB: 11.58
(note: you cut off the part about rounding so make sure that it's rounded correctly before you put in your answer)
Step-by-step explanation:
To solve this we will use SOH, CAH, TOA
we have the angle and the one opposite to it which means we can use either SOH or TOA
let's use TOA
tan(51)=(9/x)
x= 7.288
We can now use pahtagaryous theroem to solve for the hyptonouse
we have
9²+7.288²=C²
C=11.58
Finally, to find angle B we will recall that the angles of a triangle must add to 180.
51+90+a=180
a=39
Answer:
see below
Step-by-step explanation:
The experimental probability of heads is
P( heads) = 28/50 = 14/25
The theoretical probability is
P (heads) =1/2
Getting a common denominator for the experimental
25/50
comparing the experimental and the theoretical
28/50 > 25/50
experimental > theoretical
Answer:
x = 1 or x = ± i
Step-by-step explanation:
Note the sum of the coefficients
1 - 1 + 1 - 1 = 0
This indicates that x = 1 is a root, thus (x - 1) is a factor
Using long division or synthetic division, then
x³ - x² + x - 1 = (x - 1)(x² + 1), thus
(x - 1)(x² + 1) = 0
Equate each factor to zero and solve for x
x - 1 = 0 ⇒ x = 1
x² + 1 = 0 ⇒ x² = - 1 ⇒ x = ±
= ± i