Answer:
0.3902
Step-by-step explanation:
The question meets the criteria for the calculation of the confidence interval of a one sample proportion ;
Sample size, n = 27
Number of students with faster reaction time = 14
Phat = x / n = 14 / 27 = 0.6296
The confidence interval is calculated thus :
C. I = Phat ± Zcritical * √[p(1 - p)/n]
Zcritical at 99% = 2.576
C. I = 0.6296 ± 2.576 * √[0.6296(0.3704)/27]
C.I = 0.6296 ± 0.2394042
The lower boundary of C.I = 0.6296 - 0.2394042
Lower boundary = 0.3902
If the sum of all the scores is divided by the number of scores, then the MEAN has been calculated.
Answer:
5.401×10^-1
Step-by-step explanation:
You move the decimal over one to get5.401×10^−1
The answer is 100 sections. You get this by converting 2 meters which will be 200 cm then just divide 200 by 10 and you get 100! Hope this helps sorry if I get it wrong
Rewriting the left hand side,
csc²t - cost sec t
= (1/sin²t)-(cost)(1/cost)
= 1/sin²t - 1
= 1/sin²t - sin²t/sin²t
= (1-sin²t)/sin²t
= cos²t/sin²t
= cot²t
