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3 years ago

BRAINLISTS!! 35 (69) points !!

Mathematics

2 answers:

brilliants [131]3 years ago

8 0

Answer:

(A) and c

(B) and a

(D) and b

musickatia [10]3 years ago

5 0

Answer:

(A) and c

(B) and a

(D) and b

Step-by-step explanation:

these are from the calculations i got, what you do is minus the two answers you have to find n

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Kyle incorrectly says that the product of - ( - 6 ) # ( - 1 ) is 6 . 11. After a recycling awareness program, the number of tons

GaryK [48]

Complete question:

Kyle incorrectly says that the product of - ( - 6 ) # ( - 1 ) is 6 . 11. After a recycling awareness program, the number of tons of recyclable material taken to the landfill is reduced by 13 7/10 tons per month. Represent the total change in the tons of recyclable material taken to the landfill after 7 months resulting from the awareness program a. What is the correct product? 10 month. Represent the total change in the b. What was Kyle's likely error?

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Kyle incorrectly says that the product of - ( - 6 ) ( - 1 ) is 6

-(-6)(-1) = 6 [incorrect]

Correction:

-(-6) (-1) :

- (-6) = 6

6 (-1) = - 6

Given that reduction in materials = 13 7/10 tons per month

Monthly reduction = 13 7/10 = 137/10 tons

After 7 months : (7 * 137/10) = 959/10 tons = 95.9 tons

Change in amount of material taken to the land fill:

Initial amount - amount after 7 months

If initial amount = x

Change in amonnt = (x - 95.9) tons

8 0

3 years ago

Twenty-four students took a test. Fourteen students earned an A and 10 students earned a

horrorfan [7]

Total number of students who did a test was 24
Number of students who scored an A is 14
Number of students who scored a B is 10
Probability that when we randomly select a student, he/she will have an A is:
(Number of students that scored A)/(Total number of students)
=14/24
=7/12
Therefore our answer is 7/12

8 0

4 years ago

to avoid a large shallow reef a ship set a course from point a and traveled 24 miles east to point b . the ship them turn and tr

Sever21 [200]

First, we are going to find the distance traveled by the ship adding the tow distances:
Distance traveled= 24 mi +33 mi=57 mi

Next, we are going to use the Pythagorean theorem to find the distance from $a$ to $c$ :
$d^2=24^2+33^2$
$d^2=576+1089$
d^2=1665
$d= \sqrt{1665}$
$d=40.8$ mi

Finally, we are going to subtract the two distances:
57 mi -40.8 mi= 16.2 mi

We can conclude that <span>if the ship could have traveled in a straight lime from point a to point c, it could have saved 16.2 miles.</span>

7 0

4 years ago

4.) What is the exact value of sinθ when θ lies in Quadrant II and cosθ=−513

dimaraw [331]

Answer:

Part 4) $sin(\theta)=\frac{12}{13}$

Part 10) The angle of elevation is $40.36\°$

Part 11) The angle of depression is $78.61\°$

Part 12) $arcsin(0.5)=30\°$ or $arcsin(0.5)=150\°$

Part 13) $-45\°$ or $225\°$

Step-by-step explanation:

Part 4) we have that

$cos(\theta)=-\frac{5}{13}$

The angle theta lies in Quadrant II

The sine of angle theta is positive

Remember that

$sin^{2}(\theta)+ cos^{2}(\theta)=1$

substitute the given value

$sin^{2}(\theta)+(-\frac{5}{13})^{2}=1$

$sin^{2}(\theta)+(\frac{25}{169})=1$

$sin^{2}(\theta)=1-(\frac{25}{169})$

$sin^{2}(\theta)=(\frac{144}{169})$

$sin(\theta)=\frac{12}{13}$

Part 10)

Let

$\theta$ ----> angle of elevation

we know that

$tan(\theta)=\frac{85}{100}$ ----> opposite side angle theta divided by adjacent side angle theta

$\theta=arctan(\frac{85}{100})=40.36\°$

Part 11)

Let

$\theta$ ----> angle of depression

we know that

$sin(\theta)=\frac{5,389-2,405}{3,044}$ ----> opposite side angle theta divided by hypotenuse

$sin(\theta)=\frac{2,984}{3,044}$

$\theta=arcsin(\frac{2,984}{3,044})=78.61\°$

Part 12) What is the exact value of arcsin(0.5)?

Remember that

$sin(30\°)=0.5$

therefore

$arcsin(0.5)$ -----> has two solutions

$arcsin(0.5)=30\°$ ----> I Quadrant

$arcsin(0.5)=180\°-30\°=150\°$ ----> II Quadrant

Part 13) What is the exact value of $arcsin(-\frac{\sqrt{2}}{2})$

The sine is negative

The angle lies in Quadrant III or Quadrant IV

Remember that

$sin(45\°)=\frac{\sqrt{2}}{2}$

therefore

$arcsin(-\frac{\sqrt{2}}{2})$ ----> has two solutions

$arcsin(-\frac{\sqrt{2}}{2})=-45\°$ ----> IV Quadrant

$arcsin(-\frac{\sqrt{2}}{2})=180\°+45\°=225\°$ ----> III Quadrant

5 0

3 years ago

Michael is planning to ride a horse to a campsite. The sum of Michael’s weight and the combined weight of his camping supplies m

hram777 [196]

177 + s < = 0.20(1000)....where s = weight of the camping supplies
177 + s < = 200
s < = 200 - 177
s < = 23 <== so, at most, his camping supplies can weigh 23 lbs

6 0

3 years ago

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