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fredd [130]
3 years ago
15

Evaluate the following expression. You should do this problem without a

Mathematics
2 answers:
densk [106]3 years ago
8 0
I believer the answer is D
madam [21]3 years ago
3 0

Answer:ln is called the natural log, or log to the base e. ln can also be written as

So, we can write the given expression as

The property of logs is:

This mean if the number a is raised to log whose base is the same as the number a itself, then the answer will be equal to the argument of the log which is x.

In the given case, the number e and the base of log are the same. So the answer of the expression will be the argument of log which is 6.

so, we can write

Thus, the correct answer is option D

Step-by-step explanation:

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Verdich [7]

Answer:

ill help when you give the problem lol

Step-by-step explanation:

4 0
2 years ago
Can someone help me with number 8 please? Thank you.
Naddik [55]
Answer: -4 \le x \le 5
Note: to write the domain in interval notation, you'd write [-4,5]
if you need the domain in set-builder notation, then you'd write \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\}

------------------------------------------------------------------------------

Explanation:

The domain is the set of possible x input values. Look at the left most point (-4,-1). The x coordinate here is x = -4. This is the smallest x value allowed. The largest x value allowed is x = 5 for similar reasons, but on the other side of the graph.

So that's how I got -4 \le x \le 5 (x is between -4 and 5; inclusive of both endpoints)

Writing [-4,5] for interval notation tells us that we have an interval from -4 to 5 and we include both endpoints. The square brackets mean "include endpoint"

Writing \left\{x|x\in\mathbb{R}, \ -4\le x\le 5\right\} is the set-builder notation way of expressing the domain. The x\in\mathbb{R} portion means "x is a real number"

6 0
3 years ago
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ 
(2) \ ln \  b^{a} = a*ln \ b \\
(3) \ ln \ a + ln \ b = ln \ (ab) \\
(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
ln \ x + ln \  x^{2} = ln \  8^{2}  ⇒⇒⇒⇒ rule (1) and rule (2)

ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
Read 2 more answers
What the square root of 4
Aliun [14]

Answer:

2

Step-by-step explanation:

2x2=4

3 0
3 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs.
Inga [223]
-2 a b are a match. hope this helps 2-2=4
8 0
3 years ago
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