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fredd [130]
3 years ago
15

Evaluate the following expression. You should do this problem without a

Mathematics
2 answers:
densk [106]3 years ago
8 0
I believer the answer is D
madam [21]3 years ago
3 0

Answer:ln is called the natural log, or log to the base e. ln can also be written as

So, we can write the given expression as

The property of logs is:

This mean if the number a is raised to log whose base is the same as the number a itself, then the answer will be equal to the argument of the log which is x.

In the given case, the number e and the base of log are the same. So the answer of the expression will be the argument of log which is 6.

so, we can write

Thus, the correct answer is option D

Step-by-step explanation:

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elena-s [515]
The answer would be
m= -25
3 0
3 years ago
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Would you solve the equation 0.25x + 7 = 1/3x – 8 <br> using fractions or decimals? Explain please.
mamaluj [8]

Answer:

x = 180

Step-by-step explanation:

Solve the value of x :

0.25x + 7 = \frac{1}{3}x - 8

-Combine \frac{1}{3}x and 0.25x by subtracting 0.25x by \frac{1}{3}x :

0.25x - \frac{1}{3}x  + 7 = \frac{1}{3}x - \frac{1}{3}x  - 8

-\frac{1}{12}x + 7 = -8

-Subtract 7 on both sides:

-\frac{1}{12}x + 7 - 7 = -8 - 7

-\frac{1}{12}x = -15

-Multiply both sides by -12, the reciprocal of -\frac{1}{12} :

\frac{-\frac{1}{12}x}{-\frac{1}{12}} = \frac{-15}{-\frac{1}{12}}

x = -15 (-12)

x = 180

Therefore, the value of x is 180.

7 0
3 years ago
A building 220 feet casts a 100 foot long shadow. If a person stands at the end of the shadow and looks up to the top of the bui
kaheart [24]

Answer:

65.56°

Step-by-step explanation:

= We solve the above question using the Trigonometric function of Tangent

tan θ = Opposite/Adjacent

Opposite = 220 feet = Height of the building

Adjacent = 100 feet = Length of the shadow

Hence,

tan θ = 220/100

tan θ = 2.2

= arctan(2.2)

= 65.55604522°

Approximately = 65.56°

5 0
2 years ago
The number 6458 rounded to the nearest thousand
Murrr4er [49]

Answer:

6500

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The amount A of the radioactive element radium in a sample decays at a rate proportional to the amount of radium present. Given
slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

\tau = 2438.155\,yr

The particular solution of the differential equation is:

m(t) = 10\cdot e^{-\frac{t}{2438.155} }

d) The amount of radium after 300 years is:

m(300) \approx 8.842\,g

4 0
3 years ago
Read 2 more answers
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