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pashok25 [27]
3 years ago
11

Hiiii so my question is free pointtss

Physics
2 answers:
salantis [7]3 years ago
8 0
Hiiiii thanks you have a good day
Deffense [45]3 years ago
4 0
Yeayyyyy hehe thankss
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If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude
AveGali [126]

Answer: 1.5×10^10 N/C

Explanation:

E= F/q

Where E= magnitude of the electric field

F= force of attraction

q= charge of the given body

Given F= 6.5×10^-8 N

q= 4.3× 10^-18 C

Therefore, E = 6.5×10 ^-8/ 4.3×10^-18

E = 1.5×10^10 N/C

7 0
3 years ago
An ideal vapor-compression refrigeration cycle that uses refrigerant-134a as its working fluid maintains a condenser at 800 kpa
AlladinOne [14]

Answer:

P= 30.87 kw

Explanation:

find the solution below

7 0
4 years ago
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What is time taken by the stone ?
SSSSS [86.1K]

The time taken by the stone to hit the ground would be 5.12 seconds.

<h3>What are the three equations of motion?</h3>

There are three equations of motion given by  Newton

The first equation is given as follows

v = u + at

the second equation is given as follows

S = ut + 1/2×a×t²

the third equation is given as follows

v² - u² = 2×a×s

Keep in mind that these calculations only apply to uniform acceleration.

As given in the problem, a stone is dropped from the helicopter which is ascending at the speed of 19.6 m/s

height(S) = 156.8 meters

initial velocity(u) = -19.6 m/s

acceleration(a) = 9.81 m/s²

By using the second equation of motion given by newton

S = ut + 1/2at²

S = 156.8m ,u= -19.6 m/s , a= 9.81 m/s² and t =? seconds

156.8= -19.6t + 9.81t²

t = 5.12 seconds

Thus, the time taken by the stone to hit the ground would be 5.12 seconds.

Learn more about equations of motion from here,

brainly.com/question/5955789

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8 0
2 years ago
A large aquarium of height 6 m is filled with fresh water to a depth of D = 1.50 m. One wall of the aquarium consists of thick p
Vesnalui [34]

Answer

given,

height of aquarium = 6 m

Depth of fresh water = D = 1.50 m

horizontal length of the aquarium(w) = 8.40 m

total force increased when liquid is filled to depth = 4.30 m

g = 9.81 m/s²

ρ = 998 Kg/m³

force in the aquarium.

dF = PdA

F = \int PdA

F = \int \rho\ g\ y\ (wdy)

F = \rho\ g\ w \int ydy

F = \rho\ g\ w\dfrac{y^2}{2}

F = \dfrac{\rho\ g\ w\ y^2}{2}

At D = 1.5 m

F = \dfrac{980\times 9.8\times 8.4\times 1.5^2}{2}

F = 9.08 x 10⁴ N

At D = 4.30 m

F = \dfrac{980\times 9.8\times 8.4\times 4.3^2}{2}

F = 7.46 x 10⁵ N

Total force on the wall increased by

ΔF  = 74.6 x 10⁴ - 9.08 x 10⁴

ΔF  = 65.52 x 10⁴ N

5 0
3 years ago
Tell me pls<br>question: one way to protect property from damage. (hurricane) (hurricane)​
postnew [5]

Answer:

hide on a place where there is no windows take a radio

Explanation:

5 0
3 years ago
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