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3 years ago

Thus, an object with a momentum of 0 (does or does not have

Physics

1 answer:

creativ13 [48]3 years ago

5 0

Answer:

At momentum zero, kinetic energy = zero

At momentum 10, kinetic energy can never be equal to zero.

Explanation:

An object is said to have zero momentum when either its mass or its velocity is zero. Since, negetive mass doesn't exist, the velocity should be zero and this case, the object must be at rest. Momentum is zero when change in velocity is zero, but kinetic can never be zero when body is motion or has a momentum of 10.

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You hear three beats per second when two sound tones are generated. The frequency of one tone is known to be 610 Hz. The frequen

mestny [16]

Answer:

F. Either B or C

Explanation:

The beat frequency is the difference of two frequencies of two waves.

Here, one wave has frequency 610 Hz and the beat frequency is 3 beats per second.

It is not mentioned which has a higher frequency. So, there are two possiblities.

$\Delta f=|610-613|=3$

$\Delta f=|610-607|=3$

Hence, the frequency of the other wave is 613 or 607.

4 0

3 years ago

In the process of changing a flat tire, a motorist uses a hydraulic jack. She begins by applying a force of 48 N to the input pi

erik [133]

Answer:

Force that the output plunger applies to the car; F2 = 3888N

Explanation:

For a hydraulic device, the relationship between the force and the area using Pascal's principle is;

F1/A1 = F2/A2

Where;

F1 is force applied to the input piston

F2 is force that the output plunger applies to the car

A1 is Area of input piston

A2 is area of larger piston

We are given;

R2/R1 = 9

So,R2 = 9R1

F1 = 48N

Area of input piston;

A1 = π(R1)²

Area of output piston;

A2 = π(9R1)²

Since, (F1/A1) = (F2/A2)

Thus;

F1/(π(R1)²) = F2/(π(9R1)²)

If we simplify, π(R1)² will cancel out to give;

F1 = F2/9²

Thus;

F2 = 9² x F1

Plugging in 48N for F1, we have;

F2 = 9² x 48

F2 = 81 x 48

F2 = 3888N

8 0

3 years ago

A 300 g block connected to a light spring with a force constant of k = 3 N/m is free to oscillate on a horizontal, frictionless

Usimov [2.4K]

Answer:

Time period, T = 1.98 seconds

Explanation:

It is given that,

Mass of the block, m = 300 g = 0.3 kg

Force constant of the spring, k = 3 N/m

Displacement in the block, x = 3 cm

Let T is the period of the motion of the block. The time period of the block is given by :

$T=2\pi \sqrt{\dfrac{m}{k}}$

$T=2\pi \sqrt{\dfrac{0.3\ kg}{3\ N/m}}$

T = 1.98 seconds

So, the period of the motion of the block is 1.98 seconds. Hence, this is the required solution.

7 0

3 years ago

What is the frequency of an x-ray with a wavelength of 1.15 × 10 −10m?

vichka [17]

3 x 108 m/sec. 1.15 x 10-10 m 2.61 x 1018 1/s = ν Page 16 What is the speed of an electromagnetic wave that has a frequency of 7.8 x 106 Hz? practice problem 3. c = 3 x 108 m/sec.

3 0

3 years ago

How much energy will a stock tank heater rated at 1790 Watts use in a 24 hour period? 1. 1790 × 24 × 3600 Joules 2. 1790 × 24 ×

Rashid [163]

<h2>Option 1 is the correct answer.</h2>

Explanation:

Power of heater, P = 1790 W

Time used, t = 24 hours = 24 x 60 x 60 = 24 x 3600 s

We have the equation

$\texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}$

We need to find energy,

Substituting

$\texttt{Power}=\frac{\texttt{Energy}}{\texttt{Time}}\\\\1790=\frac{\texttt{Energy}}{24\times 3600}$

Energy = 1790 x 24 x 3600 J

Option 1 is the correct answer.

3 0

3 years ago