Answer : Half reaction is defined as the reaction which will be <span>either the oxidation or reduction </span>reaction<span> of particular species in a given redox </span>reaction<span>.
So as per the definition in the reaction of,
</span>
<span>
</span>
<span>
here on left and right side </span>
will get cancelled.
and we will get,
Here,
...this is oxidation reaction as Ba is getting reduced to
by losing 2 electrons.
whereas,on the other hand,
...this is reduction reaction as
is getting reduced to Zn by gaining 2 electrons.
Constant:
Test tubes
Independent:
<span>volume of gas
Dependent:
</span>
<span>amount of H2O2 </span>
Answer:
0.13 M ( 2 s.f)
Explanation:
2Cl2O5 (g)-->2Cl2(g) +5O2 (g)
rate= (17.4 M -1 .s -1 ) [Cl2O5]2
From the rte above, we can tell that our rate constant (k) = 17.4 M -1 .s -1
The units of k tells us this is a second order reaction.
Initial Concentration [A]o = 1.46M
Final Concentration [A] = ?
Time = 0.400s
The integrated rate law for second order reactions is given as;
1 / [A] = (1 / [A]o) + kt
1 / [A] = [ (1/ 1.46) + (17.4 * 0.4) ]
1 / [A] = 0.6849 + 6.96
1 / [A] = 7.6496
[A] = 1 / 7.6496
[A] = 0.13073 M ≈ 0.13 M ( 2 s.f)
The lines are violet and blue respectively.
<h3>What is the energy?</h3>
We know that the energy of the photon could be obtained by the use of the equation;
E = hf
E = energy
h = Plank's constant
f = frequency
For the first line;
E = 6.6 * 10^-34 Js * 3.45 x 10^14 Hz = 2.3 * 10^-19 J
Given that;
E = hc/λ
λ = hc/E
λ = 6.6 * 10^-34 * 3 * 10^8/2.3 * 10^-19
λ = 8.61 * 10^-7 m or 861 nm
The color is violet
For the second line;
E = 6.6 * 10^-34 Js * 6.53 xx 10^14 Hz
E = 4.3 * 10^-19 J
E = hc/λ
λ = hc/E
λ = 6.6 * 10^-34 * 3 * 10^8/4.3 * 10^-19
λ = 4.60 * 10^- 7 m or 460 nm
The color is blue
Learn more about emission spectrum:brainly.com/question/13537021
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