Thermoelectric Bridge CER: Design and Draw

Titanium has an HCP unit cell for which the ratio of the lattice parameters c/a is 1.58. If the radius of the Ti atom is 0.1445

Karolina [17]

The unit cell volume of the crystal is $V_c = 9.9084*10^-^2^3 cm^3 / unit cell$ and the density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Data;

radius = 0.1445 nm
c/a = 1.58
A = 46.88 g/mol

<h3>Unit Cell Volume</h3>

The unit cell volume can be calculated as

$V_c = 6R^2c\sqrt{3}\\$

let's substitute the values into the formula

$V_c = 6 * (1.445*10^-^8)^2 * 1.58 8 * a * \sqrt{3} \\a = 2R\\V_c = 6 * (1.445*10^-^8)^2 * 1.58* 2 * 1.445*10^-^8 * \sqrt{3}\\ V_c = 9.984*10^-^2^3 cm^3 / unit cell$

The unit cell volume of the crystal is $V_c = 9.9084*10^-^2^3 cm^3 / unit cell$

<h3>Density of Ti</h3>

The density of titanium can be calculated as

$\rho = \frac{nA}{V_c N_a}$

n = 6 for hcp
A = 46.88 g/mol
Na = Avogadro's number

let's substitute the values into the formula

$\rho = \frac{nA}{V_c Na}\\ \rho = \frac{6*46.88}{9.9084*10^-^2^3* 6.023*10^2^3} \\\rho = 4.71 g/cm^3$

The density of titanium is calculated as 4.71g/cm^3 while the literature value is 4.5 g/cm^3

Learn more on crystal lattice here;

brainly.com/question/6610542

8 0

2 years ago

γ−Butyrolactone (C4H6O2, GBL) is a biologically inactive compound that is converted to the biologically active recreational drug

Mashutka [201]

Answer:

Here's what I get.

Explanation:

The name tells me the compound is a lactone (a cyclic ester).

1. IR spectrum

1770 cm⁻¹

Esters and unstrained lactones normally absorb at 1740 cm⁻¹.

This peak is shifted to a higher frequency by ring strain.

A five-membered lactone absorbs at 1765 cm⁻¹, and a four-membered lactone at 1840 cm⁻¹.

The compound is probably a five-membered lactone.

2. NMR spectrum

2.28 m (2H)

2.48 t (2H)

4.35 t (2H)

This indicates three CH₂ groups arranged as X-CH₂-CH₂-CH₂-Y.

The X-CH₂- and -CH₂-Y signals would each be triplets, being split by the central -CH₂- group.

The central -CH₂- signal would be a multiplet, split by the non-equivalent hydrogens on either side.

The peak at 4.35 ppm indicates that the group is adjacent to an oxygen atom ( -CH₂- = 1.3; -CH₂-O- = 3.3 - 4.5).

The peak at 2.42 ppm indicates that the group is adjacent to a carbonyl group (-CH₂-C=O = 1.8 - 2.5.

The only way to fit these pieces together is if γ-butyrolactone has the structure shown below.

Confirmation:

(a) The IR spectrum shows a carbonyl peak at 1770 cm⁻¹.

(b) The NMR spectrum matches that given in the problem.

6 0

2 years ago

A solution containing 3.90 g of an unknown nonelectrolyte liquid and 9.60 g water has a freezing point of −3.33 °C. The Kf = 1.8

pantera1 [17]

Answer:

The molar mass is 227 g/mol

Explanation:

Step 1: Data given

Mass of unknown nonelectrolyte = 3.90 grams

Mass of water = 9.60 grams

Freezing point of the solution = -3.33 °C

Kf = 1.86°C/m

Nonelectrolyte has a van't Hoff factor = 1

Step 2:

If you know the number of moles, and you know that is equivalent to 1.00 g, you can get molar mass.

∆T =i*m*K f

⇒ ∆T = difference in temperature between freezing point of solution and pure water = 3.33 °C

⇒ Van't hoff factor of the nonelectrolyte = 1

⇒ molality = moles nonelectrolyte / mass water

⇒ Kf = freezing point constant = 1.86 °C/m

3.33 = (1)(m)(1.86)

m = 1.79 molal = 1.79 moles / kg H2O

Step 3: Calculate moles nonelectrolyte

molality = moles / mass H2O

moles = molality * mass H2O

Moles = 1.79 molal * 0.0096

Moles = 0.017184‬ moles

Step 4: Calculate molar mass of nonelectrolyte

Molar mass = mass / moles

Molar mass = 3.90 grams / 0.017184 moles

Molar mass = 227 g/mol

The molar mass is 227 g/mol

5 0

2 years ago

According to the text, which amino acid(s) contains a side chain..

solniwko [45]

Answer:

(b) that is hydrophobic

Explanation:

e.g, alanine

Cause, Alanine possess hydrophobic side chain and the most appropriate answer is (d) part......

Alanine is an aliphatic amino acid, because the side-chain connected to the α-carbon atom is a methyl group (-CH3), alanine is the simplest α-amino acid after glycine. The methyl side-chain of alanine is non-reactive and is therefore hardly ever directly involved in protein function..

Hope it will help you☺☺☺☺☺

3 0

2 years ago

Read 2 more answers

8. The following system contains 20.0 psi each of gases A and B in the end bulbs with an evacuated bulb in the centre. Both stop

Effectus [21]

Answer:

13.3

Explanation:

Before opening the stopcocks you have 40psi in total.

After that, those 40psi will be divided into 3bulbs, so 40/3=13.3psi for the system.

3 0

2 years ago