All categories

3 years ago

9. Explain why you can't write the formula of the ionic compound that forms between Fe and S?

Chemistry

1 answer:

dalvyx [7]3 years ago

5 0

Answer:

See explanation

Explanation:

According to Fajan's rules, the degree of covalent character of a bond depends on the relative polarizing power of ions.

Generally, ions become more polarizing when they are small and highly charged. Large negative ions are more polarizable than small ones.

A very small positive charge concentrated on a small area such as in Fe^2+ makes the ion highly polarizing. Also, a large negative ion such as S^2- is highly polarizable.

As a result of these FeS has considerable covalent character hence we can not simply write the formula of the ionic compound that forms between Fe and S?

You might be interested in

Which two substances bind using a lock-and-key mechanism?

Katen [24]

<span>The answer is the first option. Enzyme and substrate bind using a lock-and-key mechanism. Enzymes act on a specific substrate and a substrate needs a specific enzyme, this is what is called a lock-and-key mechanism. Enzymes and substtates are like a key and a lock, one is for each other.</span>

4 0

3 years ago

Read 2 more answers

I have a question about ionization energy.

ValentinkaMS [17]

Ionization energy is the measure of the extend to which the nucleus attracts the outermost electron
if ionization energy us high than force of attraction Is high so it is not easy to remove and vice versa .
hope you understand.....

5 0

3 years ago

Placing a sample of iron (II) oxide into a graduated cylinder makes the water volume increase 12.0 mL. The weight of the sample

vivado [14]

Answer:6.38

Explanation:D=76.6/12

4 0

3 years ago

(d) carbon monoxide

Irina18 [472]

Answer:

D. carbon monoxide

Hope this helps :)

6 0

3 years ago

The heat of reaction for the combustion of propane is –2,045 kJ. This reaction is: C3H8(g) +502 (g) 3CO2 (g) + 4H2O (g). Determi

Ede4ka [16]

Answer:

$\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Explanation:

Hello,

In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:

$\Delta _cH=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-5*\Delta _fH_{O_2}$

Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:

$\Delta _fH_{C_3H_8}=3*\Delta _fH_{CO_2}+4*\Delta _fH_{H_2O}-5*\Delta _fH_{O_2}-\Delta _cH\\\\\Delta _fH_{C_3H_8}=3*(-393.5)+4*(-241.8)-5*0-(-2045)\\\\\Delta _fH_{C_3H_8}=-102.7kJ/mol$

Best regards.

8 0

3 years ago