Ask question

Ask question

All categories

3 years ago

6

9. Explain why you can't write the formula of the ionic compound that forms between Fe and S?

1 answer:

dalvyx [7]3 years ago

5 0

Answer:

See explanation

Explanation:

According to Fajan's rules, the degree of covalent character of a bond depends on the relative polarizing power of ions.

Generally, ions become more polarizing when they are small and highly charged. Large negative ions are more polarizable than small ones.

A very small positive charge concentrated on a small area such as in Fe^2+ makes the ion highly polarizing. Also, a large negative ion such as S^2- is highly polarizable.

As a result of these FeS has considerable covalent character hence we can not simply write the formula of the ionic compound that forms between Fe and S?

You might be interested in

Name the element which has twice the number of electrons in its second shell as in the first shell write it's electronic configu

Basile [38]

CARBON! :) it’s the 6th element

3 0

3 years ago

How many grams are in 23.0 moles of carbon (C)?

Gnesinka [82]

276 grams of carbon in 23.0 moles

3 0

3 years ago

How does an atom become an atom of another element is

ivann1987 [24]

Can you give me the anwsers

3 0

3 years ago

"Compounds A and B react to give a single product, C. Write the rate law for each of the following cases and determine the units

olasank [31]

Answer:

Part a: <em>Units of k is </em> $M^{-2}s^{-1}$ <em> where reaction is first order in A and second order in B</em>

Part b: <em>Units of k is </em> $M^{-1}s^{-1}$ <em> where reaction is first order in A and second order overall.</em>

Part c: <em>Units of k is </em> $M^{-1}s^{-1}$ <em> where reaction is independent of the concentration of A and second order overall.</em>

Part d: <em>Units of k is </em> $M^{-3}s^{-1}$ <em> where reaction reaction is second order in both A and B.</em>

Explanation:

As the reaction is given as

$A+B \rightarrow C$

where as the rate is given as

$r=k[A]^x[B]^y$

where x is the order wrt A and y is the order wrt B.

Part a:

x=1 and y=2 now the reaction rate equation is given as

$r=k[A]^1[B]^2$

Now the units are given as

$r=k[A]^1[B]^2\\M/s =k[M]^1[M]^2\\M/s =k[M]^{1+2}\\M/s =k[M]^{3}\\M^{1-3}/s =k\\M^{-2}s^{-1} =k$

The units of k is $M^{-2}s^{-1}$

Part b:

x=1 and o=2

x+y=o

1+y=2

y=2-1

y=1

Now the reaction rate equation is given as

$r=k[A]^1[B]^1$

Now the units are given as

$r=k[A]^1[B]^1\\M/s =k[M]^1[M]^1\\M/s =k[M]^{1+1}\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k$

The units of k is $M^{-1}s^{-1}$

Part c:

x=0 and o=2

x+y=o

0+y=2

y=2

y=2

Now the reaction rate equation is given as

$r=k[A]^0[B]^2$

Now the units are given as

$r=k[B]^2\\M/s =k[M]^2\\M/s =k[M]^{2}\\M^{1-2}/s =k\\M^{-1}s^{-1} =k$

The units of k is $M^{-1}s^{-1}$

Part d:

x=2 and y=2

Now the reaction rate equation is given as

$r=k[A]^2[B]^2$

Now the units are given as

$r=k[A]^2[B]^2\\M/s =k[M]^2[M]^2\\M/s =k[M]^{2+2}\\M/s =k[M]^{4}\\M^{1-4}/s =k\\M^{-3}s^{-1} =k$

The units of k is $M^{-3}s^{-1}$

7 0

3 years ago

What is this chemical component? thanks!!!

Ainat [17]

It's just H20 but with 3 water molecules

8 0

3 years ago

Read 2 more answers