A rotation is an isometric transformation that turns every point of a figure through a specified angle and direction about a fixed point.
To describe a rotation, you need three things:
Direction (clockwise CW or counterclockwise CCW)
Angle in degrees
Center point of rotation (turn about what point?)
The most common rotations are 180° or 90° turns, and occasionally, 270° turns, about the origin, and affect each point of a figure as follows:
Mark me as brainliest! :D Hope it helps
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
<span>Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.
p=2w+2w=520=4w
w=130
Area
A=wL=130(130)= 16900 square yards</span>
The answer to the question is b
We know that Step 1 is correct, because it is just a restatement of the equation. Therefore, we can eliminate Step 1:
2(5y – 2) = 12 + 6y
In Step 2, the student tried using the Distributive Property. The Distributive Property can be written as one of the two following formulas:
a(b + c) = ab + ac
a(b – c) = ab – ac
In this case, we'll use the second formula. Substitute any known values into the equation above and simplify:
2(5y – 2) = 2(5y) – 2(2)
2(5y – 2) = 10y – 4
In Step 2, the student calculated 2(5y – 2) to equal 7y – 4. However, we have just proven that 2(5y – 2) is equal to 10y – 4.
The student first made an error in Step 2, and the correct step is:
Step 2: 10y – 4 = 12 + 6y
I hope this helps!
